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nikklg [1K]
3 years ago
12

Explicit formulas Write the first four terms of the sequence {an}n=1 infinity. 9. an=1/10n 11. an = 1 + sin(pin/2) Recurrence re

lations Write the first four terms of the sequence {an} defined by the following recurrence relations. Enumerated sequences Several terms of a sequence {an}n=1 infinity are given. Find the next two terms of the sequence. Find a recurrence relation that generates the sequence (supply the initial value of the index and the first term of the sequence). Find an explicit formula for the general nth term of the sequence. 17. {1. 1/2, 1/4, 1/8, 1/16,....} 19. {1,2,4,8,16,...} 21. {1.3,9,27,81,...}

Mathematics
1 answer:
monitta3 years ago
6 0

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

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Cound someone please help me on this, I'm stuck. ​
Katyanochek1 [597]

Negative exponents work like this:

a^{-b}=\dfrac{1}{a^b}

So, in order to evaluate a negative exponent, you simply have to invert the base, and then raise to the positive equivalent of the exponent.

As an example, here are the first three exercises:

8^{-3}=\dfrac{1}{8^3}=\dfrac{1}{512}

(-4)^{-5}=\dfrac{1}{(-4)^5}=-\dfrac{1}{1024}

2k^{-4}=\dfrac{2}{k^4}

You can work out the rest applying this logic.

5 0
3 years ago
A lawyer charges a $75 consultation fee and then $120 per hour thereafter.
Ainat [17]

Answer:

(a) The dependant veriable is the $120 per hour and the independant veriable is the $75 consultaion fee.
(b) The table of vaules for this would look like this,
\frac{C}{T} \frac{75}{0} \frac{195}{1} \frac{315}{2} \frac{435}{3} \frac{555}{4}, where C = cost and T = time.
(c) The relationship between C and T is linear, beacause with the more hours you take the cost increases.
(d) Yes, it is sensible because the points would be in line due to the steady increase of the hourly rate.

(e) For every hour spent the cost increases 120 dollars.
(f) The fixed cost is 75 dollars for consultation and the veriable cost is 120 per hour.

3 0
2 years ago
the lenght of the longer leg of a right triangle is 9 ft longer than the lenght of the shorter leg x. The hypotenuse is 9 ft sho
trasher [3.6K]

Answer:

see below

Step-by-step explanation:  5 23  8 03

the lenght of the longer leg of a right triangle is 9 ft longer than the lenght of the shorter leg x. The hypotenuse is 9 ft shorter than twice the lenght of the shorter leg.

shorter leg    = x

longer leg     = x + 9

hypotenuse  =  2x - 9

Pythagorean theorem  =    a² + b²  = c²

             shorter-leg² + longer-leg² = hypotenuse²

                         x²  +  (x+9)²  = (2x - 9)²                  solve for x

                  x² +  (x+9) (x+9)  =  (2x - 9)(2x - 9)

                 x² +  (x²+18x+81)  =  (4x² - 36x + 81)

                       (2x²+18x+81)  =  (4x² - 36x + 81)

                                          0 =   2x² -54x

                                          0 =  x(2x - 54)  

                           0 = x      and         0 = 2x -54  

                                                       54 = 2x

                                                      27 =  x

shorter leg    = 27        

longer leg     = 36

hypotenuse  =  45

divided all the values by 9 and you get a 3, 4, 5  right triangle, so the answer checks correct  

           

6 0
3 years ago
PLEASE HELP What is the x value??
Mrrafil [7]

Answer:

9

Step-by-step explanation:

21^2-19^2=80

sqaure root of 80 to the nearest 10th is

6 0
3 years ago
How do you do 5 x (4x10)=(5x4)=10​
Misha Larkins [42]
Take a picture of the problem on PhotoMath and it will break down all of your steps.
7 0
3 years ago
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