(A/B)+(C/D) anyone know how to solve or simplify this? It’s fractions

mafiozo [28]

Replace the second equation y=3x+4 into the first one:
2(3x+4)+5x=30
Now solve for x:
6x+8+5x=30
11x=30-8
11x=22
x=22/11
x=2
Finally, replace x=2 into y=3x+4
y=3*2+4
y=6+4 = 10
So the anwer is x=2, y=10

6 0

3 years ago

Abag contains 2 Snicker

alekssr [168]

Answer: the probability will be 3 because 8-5=3 and there was 8 trix bars and 5 crunch bars and which means it will be 3

Step-by-step explanation:

3 0

2 years ago

Why are online payments services necessary

Semenov [28]

In this digital age, online payment services are added services that will make bill payments easier. Online stores and businesses have cropped up and their market is worldwide. To facilitate easy exchange of goods and services, online payment services are offered. Online payment services benefit both the seller and the buyer. They buyer no longer need to go to a physical office to deposit his payment, all he has to do is lodge his debit or credit card to pay his bills or online purchases. Sellers also benefit from these services because he'll know that his buyers are not bogus and online payments are real-time transactions. Thus, making payment tracking easier for documentation purposes.

Can you mark me brainlest?

5 0

3 years ago

Read 2 more answers

Find the average value of the function f(x)=−4sin(x) on the interval [π2,3π2] and determine a number c in this interval for whic

Ber [7]

Answer:

Step-by-step explanation:

The average value theorem sets:

if f (x) is continuous in [a, b] and derivable in (a, b) there is a c Є (a, b) such that

$\frac{f(b)-f(a)}{b-a}=f'(c)$ , where

f(a)=f(π/2)=-4*sin(π/2) = -4*1= -4

f(b)=(3π/2)=-4*sin(3π/2) = -4*-1 = 4

$\frac{4-(-4)}{(3\pi/2)-(\pi/2)}=f'(c)$

$\frac{8}{\pi }=f'(c)$

$f'(x)=-4cos(x)$ ⇒

$f'(c)=-4cos(c)=\frac{8}{\pi }\\c=acos(\frac{-2}{\pi })\\$

c≅130

8 0

3 years ago

Minor surgery on horses under field conditions requires a reliable short-term anesthetic producing good muscle relaxation, minim

andreev551 [17]

Answer:

$p_v =P(t_{74}$

If we compare the p value and a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

Step-by-step explanation:

Data given and notation

$\bar X=18.81$ represent the average lateral recumbency for the sample

$s=8.4$ represent the sample standard deviation

$n=75$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a left tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu \geq 20$

Alternative hypothesis : $\mu < 20$

Compute the test statistic

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{18.81-20}{\frac{8.4}{\sqrt{75}}}=-1.227$

The degrees of freedom are given by:

$df=n-1=75-1=74$

Give the appropriate conclusion for the test

Since is a one side left tailed test the p value would be:

$p_v =P(t_{74}$

Conclusion

If we compare the p value and a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

3 0

3 years ago