4 years ago

You want at least three bratwursts or hamburgers for each of your 20 guest

Mathematics

2 answers:

kirza4 [7]4 years ago

5 0

If you put three bratwursts or hamburgers for 20 guest you get 60 bratwurst or hamburgers

Mkey [24]4 years ago

4 0

60 hamburgers or
bratwursts

You might be interested in

Which equation is correct? arccsc(x)=1/cos(x)

viva [34]

Answer:

arccsc(x)=1/cos(x)

Step-by-step explanation:

7 0

3 years ago

Sign the following values a=5 b=10 c=15

a_sh-v [17]

Answer:

a=5,b=10,c=15

1)(a+b)-5(c+a)

=(5+10)-5(15+5)

=(15)-5(20)

=15-5(20)

=10(20)

=200

2)(10×15)10(5×2)

=150×10×10

=15000

3)(a-b)+(a+b)

(5-10)+(10+5)

(-5)+15

-5+15

=10

4)(2ab-45)+a

=(2×5×10-45)+5

=(100-45)+5

=55+5

=60

7 0

3 years ago

Farmer Bob is trying to figure out how much space he has for his garden. If the sides of the garden are 10 ft and 50 ft, what is

Svetach [21]

The area of the garden 10 ft•50 ft= 500 sq ft

5 0

4 years ago

√48m^4 n^3 p^4 simplify square roots

DedPeter [7]

Answer:

4m^2np^2√3n

Step-by-step explanation:

4 0

3 years ago

Tracy recieves payments of $X at the end of each year for n years. The present value of her annuity is 493. Gary receives paymen

vladimir1956 [14]

Answer:

v = 1/(1+i)

PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493

PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748

PV(G)/PV(T) = 2748/493

{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493

3[1-v^(2n)]/(1-v^n) = 2748/493

Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)

3(1 + v^n) = 2748/493

1 + v^n = 2748/1479

v^n = 1269/1479 ~ 0.858

Step-by-step explanation:

6 0

4 years ago