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Oksanka [162]
3 years ago
13

3) You owe $1,842.66 on a credit card at a 14.5% APR. You pay $250.00 at the beginning of the month and put another $250.00 in a

savings account at a 4.0% APR. What is the difference in the amount of interest accrued between the credit card and savings account by the end of the month?
4) Using the information from problem 3, how much interest could you save by putting all $500.00 instead of just $250.00 toward the credit card at the beginning of the month?
Mathematics
2 answers:
Wittaler [7]3 years ago
8 0

3. Credit Card: (1842.66 - 250) (.145/12) = $19.24

Savings: 250(0.04/12) = $0.83  

Difference = 19.24 - 0.83 = $18.41  

4. Credit Card: (1842.66 - 500) (.145/12) = $16.22

You will save $18.41 - $16.22 = $2.19 by putting all $500 toward the higher credit card rate.  

nekit [7.7K]3 years ago
6 0

Answer:

3.) 18.41

4.) 3.02

Step-by-step explanation:

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Nikki spent $59.29 on clothing. She bought 3 shirts and a pair of pants. The pair of pants cost $21.29. If each shirt cost the s
Sergeu [11.5K]

Answer: $<u>12.66</u>


Step-by-step explanation:

59.29 - 21.21= 38.00

38 / 3= $<u>12.66</u>


5 0
4 years ago
2. Brian is filling a conic container with water. He has the container half full. The radius of the container is 5 inches and th
MakcuM [25]

Answer:

current volume of the water = 785.714 in²

Height of new container = 10 inches

Step-by-step explanation:

Radius of the container = 5 inches

Height of the container = 20 inches

Volume of the container = πR²H = (22/7) × 5² × 20 = 1571.428571428 in²

Since the container is half filled with water, volume of the water = 1571.428571428 ÷ 2 = 785.714 in²

b. Volume of cylinder = πR²H = volume of water from first container = 785.714 in²

Hence 785.714 = (22/7) × 5² × H

H = (785.714) ÷ [(22/7) × 25] = 10 inches

Height of new container = 10 inches

5 0
4 years ago
What is the mathematical induction of <br> 1+3+5+...+(2n-1)=n^2
Lena [83]
Let S(n) be the statement that

1+3+5+\cdots+(2n-1)=\displaystyle\sum_{k=1}^n(2k-1)=n^2

Check to see that S(n) holds for n=1:

\displaystyle\sum_{k=1}^1(2k-1)=1=1^2\implies S(1)\text{ is true}

Now suppose that S(N) is true, and use that assumption to show that S(N+1) must also be true. When n=N+1, you have

\displaystyle\sum_{k=1}^{N+1}(2k-1)=\sum_{k=1}^N(2k-1)+2(N+1)-1
=N^2+2(N+1)-1
=N^2+2N+1
=(N+1)^2

and so S(N+1) is also true, thus proving the statement is true for all n.
6 0
3 years ago
Can someone please help &lt;3
Nimfa-mama [501]

Answer:

number (c)

Step-by-step explanation:

I am not sure about this

4 0
3 years ago
Suppose you buy a CD for $300 that earns 3% APR and is compounded quarterly. The CD matures in 5 years. Assume that if funds are
klio [65]
Value of the CD after 3 months is given by 300(1 + 0.03 / 4) = 300(1 + 0.0075) = 300 x 1.0075 = $302.25.
Therefore, interest for 3 months = $302.25 - $300 = $2.25
4 0
4 years ago
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