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ivann1987 [24]
3 years ago
14

Asymptote of y=3(0.8)^x

Mathematics
1 answer:
MArishka [77]3 years ago
3 0

Answer:

x^2

add the top and do this to the bottom

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Please answer this correctly
Law Incorporation [45]

Answer:

Leo

Step-by-step explanation:

Its because out of all of them Leo didn't write less than anybody and nobody wrote more than him

Its says that Paula wrote less than Leo but more than everyone else so Leo wrote most

7 0
3 years ago
Rationalize the denominator of $\frac{\sqrt{32}}{\sqrt{16}-\sqrt{2}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, whe
musickatia [10]

Rationalizing the denominator involves exploiting the well-known difference of squares formula,

a^2-b^2=(a-b)(a+b)

We have

(\sqrt{16}-\sqrt2)(\sqrt{16}+\sqrt2)=(\sqrt{16})^2-(\sqrt2)^2=16-2=14

so that

\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{\sqrt{32}(\sqrt{16}+\sqrt2)}{14}

Rewrite 16 and 32 as powers of 2, then simplify:

\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{\sqrt{2^5}(\sqrt{2^4}+\sqrt2)}{14}

\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{2^2\sqrt2(2^2+\sqrt2)}{14}

\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{4\sqrt2(4+\sqrt2)}{14}

\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{16\sqrt2+4(\sqrt2)^2}{14}

\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{16\sqrt2+8}{14}

\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{8\sqrt2+4}7

So we have <em>A</em> = 8, <em>B</em> = 2, <em>C</em> = 4, and <em>D</em> = 7, and thus <em>A</em> + <em>B</em> + <em>C</em> + <em>D</em> = 21.

3 0
3 years ago
Please help me with this question
noname [10]

Answer:

arrow A

Step-by-step explanation:

6 out of 30 or 1/5 which is arrow A

3 0
3 years ago
Solve.<br>2x + 8y = 18<br>y= -x + 6<br>Enter your answer, in the form (x, y), in the boxes.​
iren2701 [21]

Answer:

it is a simultaneous equation and I used Elimination method

2x + 8y = 18(equ \: 1) \\   y =  - x + 6 \:  \\ y + x = 6 \: (equ \: 2) \\  \\ from \:( equ2) \\  \:  x = 6 - y \: (equ \: 3 )\\ sub. \: (equ3) \: in \: (equ2) \\ 2(6 - y )+ 8y = 18 \\ 12 - 2y + 8y = 18 \\ 6y = 18 - 12 \\ 6y = 6 \\  \frac{6y}{6}  =  \frac{6}{6}   \\  y = 1 \\  \\ sub. \: y \: in \: equ3 \\ x = 6 - y \\ x = 6 - 1 \\ x = 5 \\  \\  \\ y = 1 \:  \: x = 5

5 0
3 years ago
The sum of two numbers is -20. The difference of the two numbers is -48. What are the two numbers?
Lostsunrise [7]
34 and -14 as proven here:

Sum: 34 + -14 = 20
Difference: 34 - -14 = 48

just the opposite (when it says negative it gonna be positive)
3 0
3 years ago
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