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alex41 [277]
3 years ago
15

Billy has received a mediocre evaluation for the second year in a row. He knows that he has made improvements, but his superviso

r just does not seem to notice or in Billy’s opinion, care. Billy likes his job and wants to keep it. He listens to what his supervisor says and then his supervisor asks Billy to prepare a written response. Before Billy leaves the room to prepare the response, how should he respond to his supervisor?
a) He could argue each point and offer a defense.
b) He could take deep breaths and then respond nonjudgmentally.
c) He could just repeat back what he heard.
d) He could detour the conversation by asking something positive.
e) He could accept responsibility and make a change.
Business
2 answers:
aleksandrvk [35]3 years ago
7 0

Answer:

b. He could take deep breaths and then respond non judgmentally.

Explanation:

Although Billy has received a mediocre evaluation and he loves his job that he doesn't want to make a switch, in my opinion it would be the better option for Billy to take deep breaths, take a moment and then respond to his supervisor in a non judgmental way because it is of no good if he keeps on being judgmental about his supervisor and thinks that his supervisor does not care. Before making any decision further, i think billy should think non judgmentally.

Hope this clears everything. Good luck :)

Bess [88]3 years ago
6 0

Answer:

b) He could take deep breaths and then respond nonjudgmentally.

Explanation:

From the excerpt, it can be seen that Billy made conscious efforts to improve himself, is passionate about his job and at such would do anything to keep it.

Hence, in responding to his boss he should first of all take a deep breath, so as to clear his head of the negative energies or pressure. This will help him to draft a nice response without prejudice or being judgemental about his situation. He should endeavor to make the best out of the situation by showing in his write-up that he's the best fit for the job position.

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Which of the following items would require an adjusting entry at the end of each accounting period? a.Vacation pay earned by emp
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Answer: a.Vacation pay earned by employees

Explanation: Adjusting entries refers to journal entry made to ensure that some financial activity is assigned to the posting period in which the activity occurred. Their main purpose is to match incomes and expenses to appropriate accounting periods. They are made at the end of an accounting period to allocate income and expenditure to the period in which they actually occurred.

4 0
3 years ago
Suppose you purchase from a supplier at $4 per unit a part with which you assemble red widgets. on average, you use 50,000 units
joja [24]

The problem is missing some parts:

First, how many parts should you purchase each time you place an order.

H=.2*$4 = $0.80

S= $800

R = 50,000

 

Q = 2SRH

= 2(800) (50000) (.8)

= 10,000 units

 

The second question is how many timer per year will you place orders.

Required order = R/Q

= 50000/10000

= 5 times

4 0
3 years ago
A company might conduct full-scale practice drills, including closing a building and working from a remote location, in order to
ddd [48]
TRUE. A company might conduct full-scale practice drills, including closing a building and working from a remote location, in order to test its contingency plans
3 0
3 years ago
Information pertaining to Noskey Corporation’s sales revenue follows: Nov 2018 (Actual) Dec 2018 (Budgeted) Jan 2019 (Budgeted)
Pani-rosa [81]

Answer:

1) Budgeted cash collections for December 2018 from November 2018 Sales - $ 100,320

2) Budgeted total cash collections for January 2019 - $ 221,880

3)  Budgeted total cash payments for December 2018 - $ 135,420

Explanation:

Computation of cash collections for December 2018 from November 2018

Credit Sales for November 2018                                                   $ 264,000

Less: Uncollectible sales - 5 % of credit sales                              <u>$ (  13,200)</u>

Collectible sales                                                                              $ 250,800

Percentage of collectible sales in month of sales- 60 %             <u>$ (150,480)</u>

Percentage of collectible sales in next month -Dec 18 - 40 % $ 100.320  

Computation of total cash collections for January 2019

Cash collections from December sales

Credit sales for December 2018              $ 388,000

Less 5 % Uncollectible sales                    <u>$ ( 19,400)</u>

Collectible sales                                        <u>$ 366,600</u>

Collections in month subsequent to sale 40 % * $ 366,600      $  147,400    

Cash collections from Januray 2019 sales

Credit sales for Janaury 2019                  $ 196,000

Less: 5 % uncollectible sales                   <u>$(    9,800)</u>

Collectible sales                                       $  186,200                      

Collections in month of sale 60 % * $ 186,200                          <u>$    74,480</u>

Total collections for January 2019                                            <u>$ 221,880</u>

Computation of cash payments for December 2018

Purchases for December 2018 sales - 30 % of $ 388,000       $ 116,400

Purchases for January 2019 sales - 70 % of $ 196,000             <u>$ 137,200</u>

Total purchases for December 2018 on selling price             <u>$ 253,600</u>

Purchases  are 60 % of selling price - $ 253,600 * 60 %         <u> </u><u>$ 152,160</u>

Payments for December purchases  25 %      (A)                 <u> </u><u>$    38,040</u><u> </u>          

Purchases for November 2018 sales - 30 % of $ 264,000       $    79,200

Purchases for December 2018 sales - 70 % of $ 388,000       <u>$   137,200</u>

Total purchases for November 2018 on selling price             <u>$</u>    216,400

Purchases  are 60 % of selling price - $ 216,400 * 60 %         <u> </u><u>$    129,840</u>

Payments for November  purchases  75 %          (B)            <u> </u><u>$    97,380</u>

Total payment for purchases in December 2018  (A) + (B)    <u>$  135,420  </u>    

3 0
3 years ago
Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Sonbull [250]

Answer:

Mean = 47

Median = 47.38

Standard Deviation = 12.73

Explanation:

Note: You wrote " 40 manufacturing companies, but the total number of companies you actually listed is 75, definitely you meant 75.

Let y represent the range of advertising expenditure, f represent the number of companies, x represent the midpoint of the range of advertising expenditure.

y                                       f                      x                  fx                    fx²

$20 to under $30            9                     25               225               5625

$30 to under $40            13                    35               455               15925

$40 to under $50            21                    45               945              42525

$50 to under $60            18                    55               990              54450

$60 to under $70            14                     65               910               59150

                                       n = 75                           \sum fx = 3525      

\sum fx^2 = 177675

Mean, \bar{X} = \frac{\sum fx}{n}

\bar{X} = \frac{3525}{75} \\\bar{X} = 47

Standard Deviation:

SD = \sqrt{\frac{n \sum fx^2 - (\sum fx)^2}{n(n-1)} } \\SD = \sqrt{\frac{(75*177675) - (3525)^2}{75(75-1)} }\\SD = 12.73

Median:

Get the cumulative frequencies(cf)

         y                                        f                                cf

$20 to under $30                     9                                9

$30 to under $40                     13                               22

$40 to under $50                     21                               43

$50 to under $60                     18                               61

$60 to under $70                      14                              75

                                                N = 75

Median = Size of (N/2)th item

Median = Size of (75/2)th item

Median = Size of (37.5)th item

The median class = 40 to under 50

Lower limit, L₁ = 40

Cumulative frequency, cf = 22

f = 21

Class Width, h = 10

Median = L_1 + \frac{ (N/2) - cf}{f} * h\\

Median = 40 + \frac{ (75/2) - 22}{21} * 10\\

Median = 47.38

8 0
3 years ago
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