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nirvana33 [79]
4 years ago
11

Over what interval is the function in this graph increasing ?

Mathematics
1 answer:
fgiga [73]4 years ago
7 0

Answer: -4 ≤ x ≤ 1

Step-by-step explanation:

A function f(x) is called increasing in an interval [a,b] when f'(x) > 0 in the interval (a,b).

That is, in that interval, with increasing the value of x the value of f(x) increases.

Let f(x) be the function which is shown in the given diagram.

Since, by the given diagram,

In the interval (-\infty, -4), f(x) decreases as x increases,

Hence In this interval given function is decreasing.

In the interval [-4, 1], f(x) increases as x increases,

Hence In this interval given function is increasing.

In the interval (1,6), f(x) is constant as x increases,

Hence In this interval given function is neither increasing nor decreasing.

In the interval (6,\infty), f(x) decreases as x increases,

Hence In this interval given function is decreasing.

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Answer:

The number of nickel = 3

Number of dime =  1

Number of quarter  = 7

Step-by-step explanation:

Let us assume the number of nickels Meghan has = m

So, the number of dimes she has = m -2

And the number of quarters she has = 1  + 2 m

Now, the total amount she has  = $2.00

1 nickel = $0.05  ⇒  m nickel =  m ($0.05)  = 0.05 m

1 dime = $0.10 ⇒  (m -2) dime =  m-2  ($0.10)  = 0.10 (m-2)

1 quarter  = $0.25  ⇒  (1+ 2m) quarter = (1+ 2m) ($0.25)  = 0.25 (1+2m)

So, according to the question:

Amount of (nickel + dime + quarter) = $2.00

⇒  0.05 m +  0.10 (m-2) +  0.25 (1+2m) = 2

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or, 0.65 m = 2 - 0.05

or, m = 1.95/0.65 =  3

or,  m  = 3

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4 years ago
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