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2 years ago

A company’s stock was selling at $25 a share a month later it was selling at $30 a share what is the percent increase

Mathematics

1 answer:

rjkz [21]2 years ago

4 0

Answer:

20% increase

Step-by-step explanation:

To find the percent increase, you can divide the increase value by the original: 30/25 = 1.2 --> 120%. Next, since they ask for the percent of increase, you can subtract 1 or 100% from your answer which would give you a final answer of 20% increase.

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If sin(x) = 0 and cos(x) = 1, what is cot(x)?

Nata [24]

Answer:

undefined

Step-by-step explanation:

Sin(x) = 0 where x = 0

Cos(x) = 1 where x = 0

Cot(0) is undefined

3 0

2 years ago

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Messed up and didnt put the attachment on the last post

Margarita [4]

Answer :-

9(3+√3) feet

Step by step explanation :-

A triangle is given to us. In which one angle is 30° and length of one side is 18ft ( hypontenuse) .So here we can use trignometric Ratios to find values of rest sides. Let's lable the figure as ∆ABC .

Now here the other angle will be = (90°-30°)=60° .

In ∆ABC ,

=> sin 30 ° = AB / AC

=> 1/2 = AB / 18ft

=> AB = 18ft/2

=> AB = 9ft .

Again In ∆ ABC ,

=> cos 30° = BC / AC

=> √3/2 = BC / 18ft

=> BC = 18 * √3/2 ft

=> BC = 9√3 ft .

Hence the perimeter will be equal to the sum of all sides = ( 18 + 9 + 9√3 ) ft = 27 + 9√3 ft = 9(3+√3) ft .

<h3>Hence the perimeter of the triangular pathway shown is 9 ( 3 + √3 ) ft .</h3>

3 0

2 years ago

What whole number equals 5

Hoochie [10]

5 equals the whole number 5?

5 0

2 years ago

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Find 30% of 70 a. 21 b. 36 c. 40

gtnhenbr [62]

A is your answer

We can cross multiply using x/70=30%/100

Solving it we get:
100x=2100 (70 times 30)
x=21

So we get a, 21 as your answer.

I hope this helped!

8 0

3 years ago

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At noon, ship A is 170 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 20 km/h. How fast is

garik1379 [7]

Check the picture below.

now, keep in mind that ship B is going at 20kph, thus from noon to 4pm, is 4 hours, so it has travelled by then 20 * 4 or 80 kilometers, thus b = 80.

whilst the ship B is moving north, the distance "a" is not really changing, and thus is a constant, that matters because the derivative of a constant is 0.

$\bf c^2=a^2+b^2\implies \stackrel{chain~rule}{2c\cfrac{dc}{dt}}=0+2b\cfrac{db}{dt}\implies \cfrac{dc}{dt}=\cfrac{b\frac{db}{dt}}{c}
\\\\\\
\begin{cases}
\frac{db}{dt}=20\\
c=10\sqrt{353}\\
b=80
\end{cases}\implies \cfrac{dc}{dt}=\cfrac{80\cdot 20}{10\sqrt{353}}\implies \cfrac{dc}{dt}=\cfrac{160}{\sqrt{353}}
\\\\\\
\textit{and rationalizing the denominator}\implies \cfrac{160\sqrt{353}}{353}$

8 0

2 years ago