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3 years ago

What is the approximate volume of a cone with a height of 6 mm and radius of 18 mm?

Mathematics

2 answers:

notka56 [123]3 years ago

6 0

Answer:

678.24mm³

Step-by-step explanation:

The volume of the cone is computed using the formula:

$V = \pi r^2\dfrac{h}{3}$

Where:

r = radius of the circular base

h = height of the cone

π = 3.14

We are given the following:

r = 6mm

h=18mm

π = 3.14

So now that we have that, we just fill in the formula:

$V = \pi r^2\dfrac{h}{3}\\\\V = (3.14)(6mm)^{2}\dfrac{18mm}{3}\\\\V= (3.14)(36mm^2)(6mm)\\\\V = (113.04mm^{2})(6mm)\\\\V=678.24mm^{3}$

g100num [7]3 years ago

3 0

Answer:

2034.72

Step-by-step explanation: I just did the test and got it this question wrong and it said 2034.72 was the correct answer

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Darren has the option of investing in either Stock A or Stock B. The probability of the return of Stock A being 25% is 0.45, 14%

Lunna [17]

Answer:

C)A is 15.95% ,B is 11.85%

Step-by-step explanation:

We know that the expected value in probability distribution is given as

Lets X is the expected value then

$X= \sum_{i=1}^{i=n} X_i P_i$

For stock A

X=0.25 x 0.45+0.14 x 0.25+0.04 x 0.3

X=0.1595

So the expected return for A is 15.95%

For stock 9

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X=0.1185

So the expected return for B is 11.85%

So our option C will be the answer of that problem.

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3 years ago

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andrey2020 [161]

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3 years ago

Triangle JKL is fromed by plotting three points. What is the leanth of sides JK?

Phoenix [80]

<h3>Solution:-</h3>

J (1,5)
K (1,9)

$\LARGE\leadsto\sf JK=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\LARGE\leadsto\sf \sqrt {(1-1)^2+(9-5)^2}$

$\LARGE\leadsto\sf \sqrt {(0)^2+(4)^2}$

$\LARGE\leadsto\sf \sqrt {0+16}$

$\LARGE\leadsto\sf \sqrt {16}$

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2 years ago

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Elza [17]

Answer:

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2 years ago

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shtirl [24]

Answer:

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Step-by-step explanation:

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5 0

3 years ago