Answer:
Lets say that P(n) is true if n is a prime or a product of prime numbers. We want to show that P(n) is true for all n > 1.
The base case is n=2. P(2) is true because 2 is prime.
Now lets use the inductive hypothesis. Lets take a number n > 2, and we will assume that P(k) is true for any integer k such that 1 < k < n. We want to show that P(n) is true. We may assume that n is not prime, otherwise, P(n) would be trivially true. Since n is not prime, there exist positive integers a,b greater than 1 such that a*b = n. Note that 1 < a < n and 1 < b < n, thus P(a) and P(b) are true. Therefore there exists primes p1, ...., pj and pj+1, ..., pl such that
p1*p2*...*pj = a
pj+1*pj+2*...*pl = b
As a result
n = a*b = (p1*......*pj)*(pj+1*....*pl) = p1*....*pj*....pl
Since we could write n as a product of primes, then P(n) is also true. For strong induction, we conclude than P(n) is true for all integers greater than 1.
Answer:
$16.2
Step-by-step explanation:
15 x .08 [wonder how i got .08? 8% = 0.8]
= 1.2
here's where most people mess up, they usually forget to add the tax to the original cost.
15 + 1.2=
$16.2
Answer:
C
Step-by-step explanation:
Solution:-
- An experiment on the efficacy of spraying malathion on oats to control the growth cereal leaf beetle.
- A sample of n = 10 farms was taken at random. Each farm was either subjected to control group ( no spray ) or the treatment group ( spray ).
- Power ( β ) is the probability of rejecting the null hypothesis when, in fact, it is false. I.e the test statistics lie in the rejection region or the benefit of adding malathion is proven in-effective when in fact it is in-effective.
- Power is the probability of avoiding a ( Type II error ). Mathematically expressed as:
Type II Error = 1 - β
- Power is the probability of making a correct decision (to reject the null hypothesis) when the null hypothesis is false.
- The probability that a test of significance will pick up on an effect that is present.
Hence,
Answer: It is the ability to detect the effectiveness of malathion when in fact it is effective.
Answer:
Step 3, because the solution should also include all the values for x between the two given values
Step-by-step explanation:
step 1
we have
step 2
The graph in the given problem
step 3
Identify the solution when 
so
using a graphing tool
The solution is the interval -----> [3,5]
see the attached figure
All real numbers greater than or equal to 3 and less than or equal to 5
therefore
The first step in which the student made an error is step 3
Answer:
root 25
Step-by-step explanation:
root 25 is 5, and every other number may not be able to be written as a whole number (please give brainliest)
