Answer: 79
Step-by-step explanation:
Given the following :
Graduation Rates:
Grade:82
Weight: 50%
Passing Rates:
Grade: 75
Weight: 30%
Enrollment Numbers:
Grade: 60
Weight: 10%
Career readiness:
Grade: 95
Weight: 10%
Overall score : Σ(grade × weight)
(82 × 50%) + (75 × 30%) + (60 × 10%) + (95 × 10%)
= (41 + 22.5 + 6 + 9.5)
= 79
Hence, overall score is 79
Answer:
It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).
Step-by-step explanation:
We can demonstrate that Circle R is similar to Circle Q by translating the center of the former one to the center of latter one. Meaning that every point of circle R experiments the same translation. Vectorially speaking, a translation is defined by:
(1)
Where:
- Original point.
- Translated point.
- Translation vector.
If we know that 
and 
, then the translation vector is:
It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).
Answer: the answer to (g+h)x4 is
4g+4h
Step-by-step explanation:
(g+h)x4
multiply the parentheses by 4
and that will give you 4g+4h
sorry if it was wrong
Since y varies directly with x, we know that a multiplier of k will be multiplied by x.
y = kx
In order to use this equation we need to know the value of k. That is why they gave us known values of x & y.
"when y = –51, x = 3"
Plug these values into our equation and solve for k.
–51 = k(3)
–51/3 = k Divide both sides by 3
k = –17 Simplify
Now that we know k our equation from here on is:
y = –17x
Now we can use this equation to solve y if x = 2 by plugging in 2 for x.
y = –17(2)
y = –34 FINAL ANSWER
