Pentagon ABCDE ~ Pentagon FGHIJ. If CD=14, DE=19, and IJ=42, what is the length of HI.

The weight of strawberries follows a normal distribution with a mean weight of 12 grams and a standard deviation of 2.5 grams. I

Svetlanka [38]

Answer:

.2119 is the answer

Step-by-step explanation:

hope this helps

7 0

2 years ago

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Determine all real values of p such that the set of all linear combination of u = (3, p) and v = (1, 2) is all of R2. Justify yo

Rama09 [41]

Answer:

p ∈ IR - {6}

Step-by-step explanation:

The set of all linear combination of two vectors ''u'' and ''v'' that belong to R2

is all R2 ⇔

$u\neq 0_{R2}$

$v\neq 0_{R2}$

And also u and v must be linearly independent.

In order to achieve the final condition, we can make a matrix that belongs to $R^{2x2}$ using the vectors ''u'' and ''v'' to form its columns, and next calculate the determinant. Finally, we will need that this determinant must be different to zero.

Let's make the matrix :

$A=\left[\begin{array}{cc}3&1&p&2\end{array}\right]$

We used the first vector ''u'' as the first column of the matrix A

We used the second vector ''v'' as the second column of the matrix A

The determinant of the matrix ''A'' is

$Det(A)=6-p$

We need this determinant to be different to zero

$6-p\neq 0$

$p\neq 6$

The only restriction in order to the set of all linear combination of ''u'' and ''v'' to be R2 is that $p\neq 6$

We can write : p ∈ IR - {6}

Notice that is $p=6$ ⇒

$u=(3,6)$

$v=(1,2)$

If we write $3v=3(1,2)=(3,6)=u$ , the vectors ''u'' and ''v'' wouldn't be linearly independent and therefore the set of all linear combination of ''u'' and ''b'' wouldn't be R2.

7 0

2 years ago

I need help pls!! 20 points I need it!!

dolphi86 [110]

Answer: About 6.71 units

Step-by-step explanation:

You use the distance formula: $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }$ .

Assign the the two points to the variables:

$(x_{1}, y_{1}) = (1, 3)\\(x_{2}, y_{2}) = (4, -3)$

Substitute them in the formula:

$\sqrt{(4-1)^{2}+(-3-3)^{2}}$

And solve it:

$\sqrt{(4-1)^{2}+(-3-3)^{2}}\\=\sqrt{(3)^{2}+(-6)^{2}}\\=\sqrt{9+36}\\=\sqrt{45}\\=6.71$

3 0

2 years ago

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The Gotemba walking trail up Mount Fuji is about 9km long. Walkers need to return from the 18km walk by 8pm. Toshi estimates tha

stiv31 [10]

Answer:

Toshi must begin his walk at 11:00 AM in order that he can return by 8:00 PM.

Step-by-step explanation:

Since the Gotemba walking trail up Mount Fuji is about 9km long, and walkers need to return from the 18km walk by 8pm, if Toshi estimates that he can walk up the mountain at 1.5km / h on average, and down at twice that speed , these speeds taking into account meal breaks and rest times, to determine what is the latest time he can begin his walk so that he can return by 8pm the following calculation must be performed:

Climb: 1.5 km / h

Descent: 2 x 1.5 km / h = 3 km / h

Climb: 9 km / 1.5 km / h = 6 hours

Descent: 9km / 3 km / h = 3 hours

Total: 9 hours

8 PM = 20:00

20:00 - 09:00 = 11:00

Thus, Toshi must begin his walk at 11:00 AM in order that he can return by 8:00 PM.

3 0

2 years ago

(-7)(-5)= __ a0<br>solve the equation

tatuchka [14]

Answer:

-7 x -5 = 35

Step-by-step explanation:

When you multiply two numbers with the same sign they will always equal positive.

Hope this helped :)

4 0

2 years ago