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wolverine [178]

3 years ago

7

B/2+1=5 solve this equation

1 answer:

d1i1m1o1n [39]3 years ago

7 0

Answer:

b=8

Step-by-step explanation:

b/2+1=5

b/2=5-1

b/2=4

b=4×2

b=8

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In a toy store, the ratio of the number of dolls to the number of teddy bears is 6 : 5. If the store has 240 dolls, how many t

grandymaker [24]

Answer:

200 teddy bears

Step-by-step explanation:

D : TB

6 : 5

Let the total number of dolls be 6x and the total number of teddy bears be 5x.

6x = 240

5x = $\frac{5}{6}$ × 240

= 200 teddy bears

5 0

3 years ago

Solve with substitution. Show each step of your work<br><br> 4x + y = 12<br> 6x + 2y = 18

Svetach [21]

4x + y = 12
Get y by itself
Subtract 4x
y = -4x + 12

Since you know what y is, you can plug the value into the second equation

6x + 2(-4x + 12) = 18
6x - 8x + 24 = 18
-2x = -6
x = 3

Plug the value 3 into x for y = -4x + 12 in order to find y
-4(3) + 12 = y, y = 0

Solution: x = 3, y = 0

3 0

3 years ago

Can someone help me on this too!

Ann [662]

Answer:

72 signs

Step-by-step explanation:

90 min = 1.5 hour

6 hours hangs 6/1.5 * 18 signs = 72

3 0

3 years ago

Read 2 more answers

Factor 26x2-30x+9 , I would most definitely thank all of you for your tremendous amount of help with these problems I can’t seem

AVprozaik [17]

25x^2 - 30x + 9

= 25x^2 - 15x - 15x + 9

= 5x(5x - 3) - 3(5x - 3)

= (5x - 3)^2 Answer

Its the second choice

8 0

3 years ago

Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt.

qwelly [4]

Answer:

A)

$\displaystyle \frac{dy}{dt}=-\frac{33}{8}$

B)

$\displaystyle \frac{dx}{dt}=\frac{3}{2}$

Step-by-step explanation:

<em>x</em> and <em>y</em> are differentiable functions of <em>t, </em>and we are given the equation:

$xy=6$

First, let's differentiate both sides of the equation with respect to <em>t</em>. So:

$\displaystyle \frac{d}{dt}\left[xy\right]=\frac{d}{dt}[6]$

By the Product Rule and rewriting:

$\displaystyle \frac{d}{dt}[x(t)]y+x\frac{d}{dt}[y(t)]=0$

Therefore:

$\displaystyle y\frac{dx}{dt}+x\frac{dy}{dt}=0$

A)

We want to find dy/dt when <em>x</em> = 4 and dx/dt = 11.

Using our original equation, find <em>y</em> when <em>x</em> = 4:

$\displaystyle (4)y=6\Rightarrow y=\frac{3}{2}$

Therefore:

$\displaystyle \frac{3}{2}\left(11\right)+(4)\frac{dy}{dt}=0$

Solve for dy/dt:

$\displaystyle \frac{dy}{dt}=-\frac{33}{8}$

B)

We want to find dx/dt when <em>x</em> = 1 and dy/dt = -9.

Again, using our original equation, find <em>y</em> when <em>x</em> = 1:

$(1)y=6\Rightarrow y=6$

Therefore:

$\displaystyle (6)\frac{dx}{dt}+(1)\left(-9)=0$

Solve for dx/dt:

$\displaystyle \frac{dx}{dt}=\frac{3}{2}$

5 0

3 years ago