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anzhelika [568]
4 years ago
10

. Complete the pattern: 20, 20, 19, 17, 14, Next two

Mathematics
1 answer:
Anna35 [415]4 years ago
6 0

Answer:

10, 5

Step-by-step explanation:

20-0 is 20

20-1 is 19

19-2 is 17

17-3 is 14

14-4 is 10

10-5 is 5

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Find and simplify an expression for the area of two rows of b squares with side lengths of b centimeters. Please help!
Ronch [10]

Answer:

The complete area of the given figure is (2 b^3) cm^2

Step-by-step explanation:

Total number of rows = 2

Squares in each row = b

So, the total number of  squares in 2 rows = 2 x ( Squares in 1 row ) = 2 x  b

Also, side length of 1 square = b cm

As we know, AREA OF SQUARE  = SIDE x SIDE

So here, area of 1 square  = Side x side  = b cm  x b cm = (b^2) cm^2

⇒ The area of total (2b) squares  = 2 b x ( Area of  1 square)

= 2 b \times (b^2)  = 2 b^3

Hence, the complete area of the given figure is (2 b^3) cm^2

6 0
3 years ago
Identify the solution set 2(-x -9) = -2x + 8
Paha777 [63]
The answer is only one solution
6 0
3 years ago
I need help. Please give me an example
xxTIMURxx [149]

Answer:

9

Step-by-step explanation:

3/729= 9

729=9^3

=3/9^3= 9


Hope this helps! Please give brainiest!

8 0
3 years ago
Parallelogram ABCD is translated (x + 3, y − 2) and then rotated 90° about the origin in the clockwise direction. Complete the t
Darya [45]

Answer: A″ (−1, 2), B″ (1, 1), C″ (1, −1), D″ (−1, −2)

Step-by-step explanation:

  • there are basically 2 parts in the question.
  • first one is the translation(easier one)

after translation, the corresponding points will be:

A (− 5, 1)   --> a(-5+3,1-2) = (-2,-1)

B (−4, 3)  --> b(-4+3,3-2) = (-1,1)

C (−2, 3)  --> c(-2+3,3-2) = (1,1)

D (−1, 1)    --> d(-1+3,1-2)  = (2,-1)

  • now the second part:

let (x,y) be a point and if it is rotated by "\alpha"

then, the new coordinates (x',y') will be :

x'= xcos\alpha +ysin\alpha

y'=-xsin\alpha +ycos\alpha

here, \alpha = 90 degrees

so,

a(-2,-1)  --> A"(-2cos[90]-1sin[90], -[-2]sin[90]+[-1]cos[90]) =(0-1, 2+0)=(-1,2)

(since, cos[90]=0, sin[90]=1)

b(-1,1)    -->B"(-1cos[90]+1sin[90], -[-1]sin[90]+1cos[90])=(1,1)

c(1,1)     --> C"(1cos[90]+1sin[90],-[1]sin[90]+1cos[90]) = (1,-1)

d(2,-1)   --> D"(2cos[90]+[-1]sin[90],-2sin[90]+[-1]cos[90]) =(-1,-2)

these are the coordinates after both the transformations.

7 0
4 years ago
Read 2 more answers
ZDFG = (5y + 3) _<br> o<br> LEFG = (2y – 5)<br> LU
jolli1 [7]

Answer:

(5/4)

Step-by-step explanation:

4 0
3 years ago
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