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Masteriza [31]
3 years ago
11

Solve for x -2(3x+2)-2x+4=40

Mathematics
2 answers:
RoseWind [281]3 years ago
8 0

Answer:x=26

Step-by-step explanation:

katovenus [111]3 years ago
4 0

Answer:

x= -5

Step-by-step explanation:

Let's solve your equation step-by-step.

−2(3x+2)−2x+4=40

Step 1: Simplify both sides of the equation.

−2(3x+2)−2x+4=40

(−2)(3x)+(−2)(2)+−2x+4=40(Distribute)

−6x+−4+−2x+4=40

(−6x+−2x)+(−4+4)=40(Combine Like Terms)

−8x=40

Step 2: Divide both sides by -8.

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I know the answer but what’s the work
mina [271]

Answer:

(0.5r^2pi) + (0.5r^2pi) + (bh)

Step-by-step explanation:

All you need to do is to find the area of each shape, then add all areas together.

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The radius of circle A is three feet less than twice the diameter of circle B. If the sun mmm of the diameters of both circles i
yanalaym [24]

Answer:

Area of Circle A = 1133.54

Circumference of Circle A= 119.32

Step-by-step explanation:

Given: Sum of both circle diameters= 49 feet.

           Circle A radius= Three feet less than twice the diameter of circle B.

Lets assume diameter of Circle B is "x"

∴ Circle A radius (r)= (2x-3)

We know, the diameter of circle is 2r

Diameter of Circle A is 2\times (2x-3)

Next as given sum of both circle diameter is 49 feet.

∴ 2(2x-3)+x= 49\ feet

distributing 2 with 2x and -3

⇒ 4x-6+x= 49

⇒5x-6= 49

Adding both side by 6

⇒5x=55

Cross multiplying both side.

⇒x=\frac{55}{5} = 11

∴ Diameter of circle B is 11 feet.

Next, subtituting the value of x to get the value of radius for Circle A.

Radius of circle A= (2x-3)

⇒ Radius of circle A= (2\times 11-3)= 22-3

∴ Radius of circle A= 19 feet.

Area of circle= \pi r^{2}

Taking π= 3.14

Area of circle A= 3.14\times 19^{2} = 3.14\times 361

∴ Area of circle A= 1133.54

Circumference of circle= 2πr

Circumference of Circle A= 2\times 3.14\times 19= 119.32

∴ Circumference of Circle A= 119.32

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How many miles is mars from earth​
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Answer:

33.9 million miles.

Step-by-step explanation:

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How do you simplify expressions with rational exponents
Rainbow [258]

Answer:

Step-by-step explanation:

Simplify expression with rational exponents can look like a huge thing when you first see them with those fractions sitting up there in the exponent but let's remember our properties for dealing with exponents. We can apply those with fractions as well.

Examples

(a)   (p^4)^{\dfrac{3}{2}}

From above, we have a power to a power, so, we can think of multiplying the exponents.

i.e.

(p^{^ {\dfrac{4}{1}}})^{\dfrac{3}{2}}

(p^{^ {\dfrac{12}{2}}})

Let's recall that when we are dealing with exponents that are fractions, we can simplify them just like normal fractions.

SO;

(p^{^ {\dfrac{12}{2}}})

= (p^{ 6})

Let's take a look at another example

\Bigg (27x^{^\Big{6}} \Bigg) ^{{\dfrac{5}{3}}}

Here, we apply the \dfrac{5}{3} to both 27 and x^6

= \Bigg (27^{{\dfrac{5}{3}}} \times x^\Big{\dfrac{6}{1}\times {{\dfrac{5}{3}}} }\Bigg)

= \Bigg (27^{{\dfrac{5}{3}}} \times x^\Big{\dfrac{2}{1}\times {{\dfrac{5}{1}}} }\Bigg)

Let us recall that in the rational exponent, the denominator is the root and the numerator is the exponent of such a particular number.

∴

= \Bigg (\sqrt[3]{27}^{5} \times x^{10} }\Bigg)

= \Bigg (3^{5} \times x^{10} }\Bigg)

= 249x^{10}

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3 years ago
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