Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Answer:
The sum of reciprocals is 2/3.
You don't need complex numbers to solve this, but if you try to find a and b you will need complex numbers.
Step-by-step explanation:
a+b = 2
a*b = 3
1/a + 1/b = x
(a*b)*(1/a + 1/b) = (a*b)x
b + a = (a*b)(x)
2 = 3x
x = 2/3
b = 2 - a
a*(2 - a) = 3
-a^2 + 2a = 3
-a^2 + 2a - 3 = 0
a^2 - 2a + 3 = 0
let's solve the quadratic equation
a^2 - 2a + 3 = a^2 - 2a + 1 + 2 = (a - 1)^2 + 2 = 0
(a - 1)^2 = -2
these options correspond to a and b from the original question.
Answer:
Two equal sides = 14.4 inches each
Shortest side = 7.2 inches
Step-by-step explanation:
a + b + c = 36
a = b
a = 2c
then:
c = a/2
a + a + a/2 = 36
2a + a/2 = 36
4a/2 + a/2 = 36
5a/2 = 36
a = 2*36/5
a = 72/5
a = 14.4
a = 2c
14.4 = 2*c
c = 14.4/2
c = 7.2
a = b
b = 14.4
Check:
14.4 + 14.4 + 7.2 = 36
Answer:
3.6 minutes.
Step-by-step explanation:
According to the data given in the question, between 9 and 10 AM, 220 passengers have checked in which means that the check-in rate is 3.6 passengers per minute. If the average number of passengers waiting for check-in is 32 and if we assume that the check-in rate is constant throughout the day, then the average passenger had to wait in line for 3.6 minutes.
X = 4
First take 12x off both sides, so -7x=-28
The negatives cancel out, so 7x=28
Not find the hcf and divide by that.
