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<h3>Answer</h3>
a = 36
b = √3/5
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<h3>Known </h3>
Adjuscent = 12√3
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<h3>Question</h3>
Opposite = ?
Hypotenuse = ?
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<h3>Way to do</h3>
• finding a - opposite
#use tan formula
tan(∅) = opposite / adjuscent
tan(60) = opposite / 12√3
opposite = tan(60) × 12√3
opposite = 36
•finding b - hypotenuse
#use cos formula
cos(∅) = adjuscent / hypotenuse
cos(60) = 12√3 / hypotenuse
hypotenuse = 12√3 : cos(60)
hypotenuse = √3/5
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Answer:
Answer 24 cm^3
Step-by-step explanation:
If the dimensions are 1/2 the volume is 1/8 the original volume. There are 2 ways to do this. I'm going to choose the most straight forward.
Formula
V = L * w * h
Givens
L = 6
w = 8
h = 4
Solution
V_original = 6 * 8 * 4 = 192
V_half = 3 * 4 * 2 = 24
V_original / V_half = 192/24 = 8/1
So the other way around (V_half/V_original) = 1/8
First put them into improper fractions which are 77/19 and 31/21, then multiply 77 and 31 and get 2387, and multiply the denominators 19 and 21 which is 399. Then u can put it into a simplified fraction of u wnat
Cube root 27 = 3
So cube root of 30 is greater than 3
Between 3 and 4
Answer:
To start off, this fraction needs to be rationalized; you can't have a radical in the denominator. So, you multiply both the numerator & denominator by the same number (so as to not mess up the proportion of numerator:denominator; it's like multiplying by 1) & get the radical out of the denominator. What number would that be? sqrt5.
So we have (sqrt6/sqrt5)•(sqrt5/sqrt5).
To simplify that, we get (sqrt6•sqrt5)/(sqrt5•sqrt5).
This can be rewritten as:
sqrt(6•5)/sqrt(5•5)
= sqrt30/sqrt25
Now, sqrt25 = 5, so that problem is solved as such:
sqrt30/5
I'm thinking sqrt30 can't be simplified any further. If it can, do so.
Hope this helps!
Step-by-step explanation: