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4 years ago

Y equals 5x to the second power

Mathematics

1 answer:

Katena32 [7]4 years ago

3 0

Idk im just learning that at school

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Write 4.625 as a mixed number in simplest form

Zarrin [17]

4 625/1,000 to 4 25/40 to 4 5/8

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4 years ago

Calculate the protein intake of Tim Worker who weighs 160 lb. using the 0.45 factor.How much protein should he intake?

klio [65]

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3 years ago

Read 2 more answers

At the beginning of an experiment, a scientist has 300 grams of radioactive goo. After 150 minutes, her sample has decayed to 37

monitta

Answer:

Half-life of the goo is 49.5 minutes

$G(t)= 300e^{-0.014t}$

191.7 grams of goo will remain after 32 minutes

Step-by-step explanation:

Let $M_0\,,\,M_f$ denotes initial and final mass.

$M_0=300\,\,grams\,,\,M_f=37.5\,\,grams$

According to exponential decay,

$\ln \left ( \frac{M_f}{M_0} \right )=-kt$

Here, t denotes time and k denotes decay constant.

$\ln \left ( \frac{M_f}{M_0} \right )=-kt\\\ln \left ( \frac{37.5}{300} \right )=-k(150)\\-2.079=-k(150)\\k=\frac{2.079}{150}=0.014$

So, half-life of the goo in minutes is calculated as follows:

$\ln \left ( \frac{50}{100} \right )=-kt\\\ln \left ( \frac{50}{100} \right )=-(0.014)t\\t=\frac{-0.693}{-0.014}=49.5\,\,minutes$

Half-life of the goo is 49.5 minutes

$\ln \left ( \frac{M_f}{M_0} \right )=-kt\Rightarrow M_f=M_0e^{-kt}$

So,

$G(t)= M_f=M_0e^{-kt}$

Put $M_0=300\,\,grams\,,\,k=0.014$

$G(t)= 300e^{-0.014t}$

Put t = 32 minutes

$G(32)= 300e^{-0.014(32)}=300e^{-0.448}=191.7\,\,grams$

7 0

3 years ago

explain how you could use the greatest common factor of 8 and 20 in the distributive property to write 8 + 20 as a product

GenaCL600 [577]

Answer: 4(5+2) or 4(2+5)

Step-by-step explanation:

8 = 2*2*2

20 = 2*2*5

4(5+2) = 20+8

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3 years ago

Find the average value of the function over the given solid. The average value of a continuous function f(x, y, z) over a solid

ratelena [41]

Compute the volume of $Q$ :

$\displaystyle\iiint_Q\mathrm dV=\int_0^2\int_0^{2-x}\int_0^{2-x-y}\mathrm dz\,\mathrm dy\,\mathrm dx=\frac43$

Integrate $f(x,y,z)=x+y+z$ over $Q$ :

$\displaystyle\iiint_Qf(x,y,z)\,\mathrm dV=\int_0^2\int_0^{2-x}\int_0^{2-x-y}(x+y+z)\,\mathrm dz\,\mathrm dy\,\mathrm dx=2$

So the average value of $f$ over $Q$ is 2/(4/3) = 3/2.

4 0

4 years ago