All categories

3 years ago

–15d – 12 = –4(d + 3) – 11d

Mathematics

2 answers:

Daniel [21]3 years ago

8 0

The correct awnser is they are all real numbers I hope I helped u

Luden [163]3 years ago

5 0

-15d - 12 = -4(d + 3) - 11d
-15d - 12 = -4d - 12 - 11d
-15d - 12 = -15d - 12
+12 +12
--------------------------------------------
-15d = -15d
---------------------------------------------

All real numbers are the solution.

You might be interested in

Find the values of x and y. lines that appear to be tangent are tangent

Ket [755]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value of $y = 122^o$

The value of $x = 61^o$

Step-by-step explanation:

Generally the total angle that make up a circle is

$\theta _T = 360$

From the diagram we see that

$\theta _T = y^o + 238^o$

=> $y^o = 360 -238$

$y^o = 122^o$

Generally angle that is formed as a result of interception of a chord and a tangent is equal to the intercepted arc divided by 2

This implies that

$x = \frac{y}{2}$

substituting values

$x = \frac{122}{2}$

$x = 61^o$

4 0

3 years ago

What is the definition of mean???

Scilla [17]

Mean, in terms of math, is the total added values of all the data in a set divided by the number of data <em>in</em> the set. Make sense? If not, here' an example...

Let's say this is my data set:
1, 2, 5, 4, 3, 8, 7, 4, 6,10

To find the mean...
Step 1: Add all of them together.
1+2+5+4+3+8+7+4+6+10 is what? 50. Now that you have this number...
Step 2: Divide by the amount there are. Basically, count up all of the numbers. How many are there? There are 10. Finally...
Step 3: Divide. 50/10 is 5, so the mean of this data set would be 5. Get it? I sure hoped this helped :)

3 0

3 years ago

How to bypass school chromebook and download games?

charle [14.2K]

Answer:

chromebooks cant download games with or without a school filter

however, if you search "unblocked games" you might find some not blocked games

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

HELPPP!!!<br> Area of Composed Figures.