Ask question

Ask question

All categories

3 years ago

15

Two sides of an obtuse triangle measure 9 inches and 14 inches. The length of longest side is unknown. What is the smallest poss

ible whole-number length of the unknown side? 16 inches 17 inches 24 inches 25 inches

1 answer:

Fofino [41]3 years ago

6 0

Answer:

126.

Step-by-step explanation:

also, Rounded to 17.

You might be interested in

Find the coordinates of the point of intersection of the graphs of lines: y=1−2x and y=x−5

koban [17]

To find the point of intersection, you have to set them equal to each other.

$1 - 2x = x - 5\\\\-2x - x = -5 - 1\\\\-3x = -6\\\\x = 2$

To find the y-value, plug in 2 into one of the equations:

y = 2 - 5

y = -3

Point of intersection: (2, -3)

5 0

3 years ago

Brian invests £4000 into his bank account.

GuDViN [60]

Answer:

10.24 years

Step-by-step explanation:

The computation of the time period is as follows:

As we know that

Amount = Principal × (1 + rate of interest)^time period

£8000 = £4000 × (1 + 0.07)^time period

£8,000 ÷ £4,000 = 1.07^time period

2 = 1.07^time period

Now apply the log to the both sides

log 2 ÷ log 1.07 = time period

= 10.24 years

7 0

3 years ago

An oarsman can row his boat 3 mph in still water. He sets out on the Illinois River, which flows at 5 mph. We are interested in

Artyom0805 [142]

Answer:

The speed from the observer is 8 mph.

Step-by-step explanation:

When the boat is going downstream with full force, its speed will be the one the oarsman can row on still water added by the flow of the river. In this case he can row the boat at speed of 3 mph, while the stream is 5 mph, so the speed from the observer standpoint is:

$speed = 3 + 5\\speed = 8 \text{ mph}$

The speed from the observer is 8 mph.

4 0

3 years ago

Find the equation of the tangent line to the curve (a lemniscate)

olya-2409 [2.1K]

Answer:

$m=\frac{9}{13}$ and $b=\frac{40}{13}$

Step-by-step explanation:

The equation of curve is

$2(x^2+y^2)^2=25(x^2-y^2)$

We need to find the equation of the tangent line to the curve at the point (-3, 1).

Differentiate with respect to x.

$2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})$

$4(x^2+y^2)(2x+2y\frac{dy}{dx})=25(2x-2y\frac{dy}{dx})$

The point of tangency is (-3,1). It means the slope of tangent is $\frac{dy}{dx}_{(-3,1)}$ .

Substitute x=-3 and y=1 in the above equation.

$4((-3)^2+(1)^2)(2(-3)+2(1)\frac{dy}{dx})=25(2(-3)-2(1)\frac{dy}{dx})$

$40(-6+2\frac{dy}{dx})=25(-6-2\frac{dy}{dx})$

$-240+80\frac{dy}{dx})=-150-50\frac{dy}{dx}$

$80\frac{dy}{dx}+50\frac{dy}{dx}=-150+240$

$130\frac{dy}{dx}=90$

Divide both sides by 130.

$\frac{dy}{dx}=\frac{9}{13}$

If a line passes through a points $(x_1,y_1)$ with slope m, then the point slope form of the line is

$y-y_1=m(x-x_1)$

The slope of tangent line is $\frac{9}{13}$ and it passes through the point (-3,1). So, the equation of tangent is

$y-1=\frac{9}{13}(x-(-3))$

$y-1=\frac{9}{13}(x)+\frac{27}{13}$

Add 1 on both sides.

$y=\frac{9}{13}(x)+\frac{27}{13}+1$

$y=\frac{9}{13}(x)+\frac{40}{13}$

Therefore, $m=\frac{9}{13}$ and $b=\frac{40}{13}$ .

5 0

2 years ago

(35 + 5)[16 + (12 divide 4)]

nadezda [96]

Answer:

59

Step-by-step explanation:

8 0

3 years ago