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Gwar [14]
3 years ago
15

Two sides of an obtuse triangle measure 9 inches and 14 inches. The length of longest side is unknown. What is the smallest poss

ible whole-number length of the unknown side? 16 inches 17 inches 24 inches 25 inches
Mathematics
1 answer:
Fofino [41]3 years ago
6 0

Answer:

126.

Step-by-step explanation:

also, Rounded to 17.

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Is there a picture for this if so can you post it
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Fathi has \$1.10$1.10dollar sign, 1, point, 10 in his printing account. Each sheet of paper he uses reduces his printing account
Katena32 [7]

Answer:

$-4.90.

Step-by-step explanation:

Fathi has $1.10. Each sheet costs him $0.25. He wants to print 47 pages.

If he prints double sided, then he will use 47 / 2 = 23.5 sheets of paper. But he can't print a half-sheet, so he will use 24 sheets of paper.

Each sheet costs $0.25. 0.25 * 24 = 6. The printing will cost him $6.

Since he only has $1.10, his remaining balance will be 1.1 - 6 = -4.9. The balance on his printing account will be $-4.90.

Hope this helps!

4 0
3 years ago
Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a
Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.064

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

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Y = 2x<br> 3x-y=15<br><br> Solve By Substitution
Minchanka [31]
The answer is X=15...
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3 years ago
Read 2 more answers
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