Answer:
<u>D. </u>
Explanation:
<em>Remember,</em><em> in a</em> limit function<em> </em><em>any number greater than zero the limit to infinity is infinity, and for numbers lesser than zero the limit is zero.</em>
<em>P (X) = </em>
<em />
<em>Q (X) = </em>
<em />
Rearranging the equation q (x) we have q (x) = 
Answer:
Approximately 22,000 metric tonnes of fish per year
Explanation:
From the graph,
Rate of decline :
(metric tonnes of fish in 1965 - metric tonnes of fish in 1995) / range of years
(700,000 - 40,000)metric tonnes ÷ (1995 - 1965)
660,000 metric tonnes ÷ 30 years
660,000 / 30
= 22,000 metric tonnes per year
Approximately 22,000 metric tonnes of fish per year
Answer:
square metres of plant materials required to support the fox = 3650 m²
Explanation:
From the given information:
the daily caloric requirement of the fox = 800
In a year, we have = 800 kcal × 365 /year = 292,000 kcal/year
Also, only 10% of the energy at a particular trophic level can be passed onto the next.
the net productivity of the plant material = 8000 kcal/m²/yr
So, using 10% of energy at a particular level, the fox only need 80 kcal/m²/yr
The objective is to determine in square meters, how many materials are required to support the fox.
square metres of plant materials required to support the fox = 
= 3650 m²
Answer:
"she" is back (by she i mean the person who pinned hazbin)
Explanation:
*starts breathing quikly* w-what if she h-hurts him