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4 years ago

Can anybody explain how to find range on a data set?

2 answers:

6 0

To find the range of a set of numbers, you must find the lowest number and the greatest numbers.

For example - (12, 14, 15, 22, 23)

The least is 12 while the greatest is 23.

Just subtract the highest and lowest to find the range.

12 - 23 = 11

nekit [7.7K]4 years ago

4 0

so lets say your number set is

9 4 7 3 1 6
you take highest and lowest number so 9 and 1
then subtract 9 - 1 = 8 there you have it

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Given that PQRS≅WXYZ, find the corresponding parts.

scoundrel [369]

Answer:

wz is the corresponding part

Step-by-step explanation:

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2 years ago

What is half of £5.20??

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3 years ago

The length of the rectangular field is 18cm, and the width is 24cm,

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84 Ans.

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3 years ago

Read 2 more answers

Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

$(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\$ .

if we make dy/dx subject of formula we arrive at

$(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

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4 years ago

Someone help me I forgot about this I need the answer

bekas [8.4K]

The answer is B because -3.62 is less than -3.5 and greater than -3.8.

8 0

3 years ago