Probability is the mathematics of chance. In other words, it is the fraction or percentage of a certain event successfully happening. For this problem, you want to determine the probability of selecting 9, 10, 11, 12, 13 or 14 girls. The solution is as follows:
P = nCr p^r q^n-r
where
n is number of total events (n = 14)
r is the number of events that could happen (9, 10, 11, 12 ,13 and 14)
p is the probability of an event being a girl (p = 50% or 0.5)
q is the probability of either an event being a boy (q = 1-p = 0.5)
nCr is a combination formula which is n!/(r!(n-r)!)
P = [14C9* (.5)^9 * (0.5)^5]+ [14C10* (.5)^10 * (0.5)^4]+[14C11* (.5)^11 * (0.5)^3]+[14C12* (.5)^12 * (0.5)^2]+[14C13* (.5)^13 * (0.5)^1]+[14C14* (.5)^14 * (0.5)^0]
P = 0.211 or 21.1%
Answer:
I mean what’s clever
Step-by-step explanation:
Answer:6
Step-by-step explanation: first you find some factors of each number. 12- 1, 2, 3, 4, 6. 30- 1,2,3,5,6,10,15. They both have a 6 as a factor and it is the highest.
12 - 7 = 5. 5 more cycles of adding 25 to y would give you 300
The second one is counting by twos. 2 more cycles to reach 12 so add 2 x 60 to 300 =
420 (blaze it)
Hope this helped
