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andriy [413]
3 years ago
15

What is the solution to the system of equations y=-3x-2

Mathematics
2 answers:
Elan Coil [88]3 years ago
6 0

Answer:

Step-by-step explanation:

Yoo mama

vredina [299]3 years ago
5 0
Y=-3x-2 solve for y . Y=-6
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Aaron rides his bike at a constant rate of 10 miles per hour. Which table represents y, the number of miles Aaron rides his bike
Tema [17]

Answer:

I believe the answer is c. but I'm not too sure.

Step-by-step explanation:

my reasoning for this is because it's the chart that is constant. y starts out with 5=0.5 & they add five more on y's side. & x increased the same amount throughout the chart.

5 0
3 years ago
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How do you solve interquartile range?
77julia77 [94]
By Hand
Step 1: 
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 2: 
Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 3: 
Place parentheses around the numbers above and below the median. 
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).

Step 4: 
Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7),  9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.

Step 5: 
Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
5 0
3 years ago
Read 2 more answers
Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

3 0
3 years ago
Calculate the average rate of change for given function, from x=2 to x=7
LenaWriter [7]
"When you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. f(x) = x2 and f(x + h) = (x + h) Therefore, the slope of the secant line between any two points on this function is 2x + h."
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3 years ago
The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the nu
inessss [21]
The numbers are 4,8, and 14 because 4+8+14=26 an 4x2=8 and 8+6=14
7 0
3 years ago
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