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3 years ago

I need help ASAP if you can help you are amazing.

Mathematics

1 answer:

olchik [2.2K]3 years ago

3 0

Answer (Note: the bold are answers):

First question answer:

Point = (3,1)

Slope = 3

y = 3x + b

(1) = 3(3) + b

1 = 9 + b

1 - 9 = b

-8 = b

y = 3x - 8

The second question answer:

y = mx + b

Get two points:

(3,-7) and (4,-11)

m = -11 - (-7) / 4 - 3

m = -11 + 7 / 1

m = -4 / 1

m = -4

b = + 3

y = -4x + 3

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Step-by-step explanation:

Observe the figure attached.

The distance between the walls is:

$DE=AD+AE$

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Both triangles are right triangles. Therefore, you can calculate the distance between the walls as following:

- Calculate the distance AD:

$cos\alpha=\frac{adjacent}{hypotenuse}\\\\cos(60\°)=\frac{AD}{60}\\AD=30m$

- Calculate the distance AE:

$tan\beta =\frac{opposite}{adjacent}\\\\tan(45\°)=\frac{40}{AE}\\\\AE=\frac{40}{tan(45\°)}\\\\AE=40m$

Therefore the distance between the walls is:

$DE=30m+40m=70m$

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