All categories

3 years ago

Let f(x) = 5x – 3 and g(x) = -2x + 7. Find f(x) + g(x).

Mathematics

1 answer:

notka56 [123]3 years ago

5 0

f(x) + g(x) = 5x - 3 - 2x + 7

= 3x + 4

Hope this helps! If you have any questions, feel free to ask.

You might be interested in

Please help me with these questions

Scrat [10]

3. Answer: y = 4

<u>Step-by-step explanation:</u>

Need to find the slope (m):

$\dfrac{y_2-y_1}{x_2-x_1}$

$\dfrac{4 - 4}{-3-1}$

= $\dfrac{0}{-4}$

= 0

Now input ONE of the points (1, 4) and the slope (m = 0) into the Point-Slope formula:

y - y₁ = m(x - x₁)

y - 4 = 0(x - 1)

y - 4 = 0

y = 4

********************************************************************

4. Answer: $\bold{y = \dfrac{2}{3}x + 3}$

<u>Step-by-step explanation:</u>

$y - y_1 = m(x - x_1)$

$y - 1 = \dfrac{2}{3}(x - (-3))$

$y - 1 = \dfrac{2}{3}(x + 3)$

$y - 1 = \dfrac{2}{3}x + 2$

$y = \dfrac{2}{3}x + 3$

3 0

3 years ago

Manuel bought x x movie tickets for $6.50 each and y y bags of popcorn for $2.50 each. write an algebraic expression for the tot

Alekssandra [29.7K]

6.50x+2.50y = total
with x = # of movie tickets
with y= # of bags of popcorn

5 0

3 years ago

Positive five can also be expressed as which of the following?

Katarina [22]

Answer: The first one; Plus 5

Step-by-step explanation: The rest of the answers are all negative 5.

7 0

3 years ago

Read 2 more answers

I suck at graphing, can someone show me how to do this?

Stella [2.4K]

Use desmos graphing calculator

7 0

3 years ago

Two vertical poles of lengths 11 ft and 14 ft stand 16 ft apart. A cable reaches from the top of one pole to some point on the g

Alex17521 [72]

We are given

total length of cable is 30 feet

and this cable is on hypotenuse sides of the triangles

so, we can draw triangle as

Let's assume those hypotenuse as 'a' and 'b'

so, we will have

$a+b=30$

now, we can find 'a' and 'b' from triangle

Smaller triangle:

$a=\sqrt{x^2+11^2}$

Larger triangle:

$b=\sqrt{(16-x)^2+14^2}$

we know that

$a+b=30$

so, we can plug this value

and we get

$\sqrt{x^2+11^2}+\sqrt{(16-x)^2+14^2} =30$

now, we can solve for x

$\left(\sqrt{x^2+11^2}\right)^2=\left(30-\sqrt{\left(16-x\right)^2+14^2}\right)^2$

$32x-1231=-60\sqrt{x^2-32x+452}$

$1024x^2-78784x+1515361=3600x^2-115200x+1627200$

now, we can use quadratic formula

we get

$x=\frac{-\sqrt{36416^2-1152389056}+36416}{5152},\:x=\frac{\sqrt{36416^2-1152389056}+36416}{5152}$

$x=4.510,x=9.627$

so,

The point should be located 4.510 feet , 9.627 feet from the smaller pole to use 30 feet cable............Answer

6 0

3 years ago