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2 years ago

Can someone help me w this ? whoever gets it right gets brainliest

Mathematics

1 answer:

Alchen [17]2 years ago

4 0

Answer:

1) 144 ft

2) 292.5 ft

Step-by-step explanation:

1) SA= lw+ 4(1/2( <em>l </em>)h)

SA=6*6+ 4(1/2( 6 )9)

SA=36+ 4(1/2( 6 )9)

SA=36+ 4( 3*9 )

SA=36+ 4( 27 )

SA=36+ 144

2) SA= 1/2( / )h+ 3(1/2( <em>l </em>)h)

SA=1/2( 15 )13+ 3(1/2( 10 )13)

SA=7.5*13+ 3 ( 5*13 )

SA=7.5*13+ 3 ( 65 )

SA= 97.5+ 3 ( 65 )

SA=97.5+ 195

SA= 292.5

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What is the length of the missing side of the triangle? The figure is not drawn to scale.

NARA [144]

Answer:

Step-by-step explanation:

add all the numbers together to get your answer and divide it by two.

6 0

2 years ago

Read 2 more answers

HELP HOW DO I SOLVE THE FOLLOWING? PLEASE HELP

levacccp [35]

$f(x) = \sqrt[3]{2x - 1} \\f(14) = \sqrt[3]{2(14) - 1} \\f(14) = \sqrt[3]{28 - 1} \\f(14) = \sqrt[3]{27} \\f(14) = 3$

$f(x) = \sqrt[3]{2x - 1} \\f(-62) = \sqrt[3]{2(-62) - 1} \\f(-62) = \sqrt[3]{-124 - 1} \\f(-62) = \sqrt[3]{-125} \\f(-62) = -5$

$f(x) = \sqrt[3]{2x - 1} \\f(20) = \sqrt[3]{2(20) - 1} \\f(20) = \sqrt[3]{40 - 1} \\f(20) = \sqrt[3]{39}$

4 0

2 years ago

(b) If the sum of two consecutive odd numbers is 48, find the numbers.

Rudiy27

Answer:

23, 25

Step-by-step explanation:

let the first number be represented as A, since there are two odd numbers, the second number would be A + 2

A + A+2 = 48

2A + 2 = 48

2A = 48 - 2

2A = 46 ( divide both sides by 2)

A = 23

since we know the next number to be A + 2

= 23 + 2 = 25

the two numbers are 23 and 25

6 0

2 years ago

Find the area of each regular polygon. Round to the nearest tenth.

miskamm [114]

Given:

A regular polygon with three vertices and side 14 cm.

To find:

Area of the regular polygon.

Solution:

We know that, a regular polygon has equal sides and equal interior angles.

The given regular polygon has three equal sides, it means it is an equilateral triangle.

The area of an equilateral triangle is:

$A=\dfrac{\sqrt{3}}{4}a^2$

Where, a is the side length of the triangle.

Putting $a=14$ , we get

$A=\dfrac{\sqrt{3}}{4}(14)^2$

$A=\dfrac{\sqrt{3}}{4}(196)$

$A=84.87049$

$A\approx 84.9$

Therefore, the area of given regular polygon is 84.9 cm².

6 0

2 years ago

a. Calculate the volume of the solid of revolution created by rotating the curve y = 3 + 3 exp(-5 x) about the x-axis, for x bet

miskamm [114]

Answer:

A) The volume of solid is 18π cubic unit.

B) The volume of sphere is $\dfrac{4}{3}\pi r^3$

a = -r , b = r , $f(x)=\sqrt{r^2-x^2}$ and $V=\dfrac{4}{3}\pi r^3$

Solution A)

The given curve, $y=3+3e^{-5x}$ rotate about x-axis between 2 to 4.

Please find attachment for solid figure or rotation.

Using disk method to find the volume rotation about x-axis

$V=\int_a^b\pi R^2dx$

where, a = 2, b= 4 , $R=y=3+3e^{-5x}$ and dx is thickness of disk.

$V=\int_2^4\pi (3+3e^{-5x})^2dx$

$V=9\pi\int_2^4(1+e^{-10x}+2e^{-5x})dx$

$V=9\pi(x-\dfrac{1}{10}e^{-10x}-\dfrac{2}{5}e^{-5x})|_2^4)$

$V=9\pi(4-\dfrac{1}{10}e^{-40}-\dfrac{2}{5}e^{-20}-2+\dfrac{1}{10}e^{-20}-\dfrac{2}{5}e^{-10}))$

$V=9\pi (2-0)$

$V=18\pi$

Hence, the volume of solid is 18π cubic unit

Solution B)

The equation of circle of radius r and centered at origin (0,0).

$x^2+y^2=r^2$

$y=\sqrt{r^2-x^2}$

The solid form is sphere of radius r.

Using disk method, to find volume of solid

$V=\int_a^b\pi R^2dx$

where, a = -r, b = r , $R=y=\sqrt{r^2-x^2}$ and dx is thickness of disk.

$V=\int_{-r}^r\pi (r^2-x^2)dx$

$V=\pi(r^2x-\dfrac{x^3}{3})|_{-r}^r$

$V=\pi(2r^3-\dfrac{2r^3}{3})$

$V=\dfrac{4}{3}\pi r^3$

Hence, the volume of sphere is $\dfrac{4}{3}\pi r^3$

4 0

3 years ago