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Aliun [14]
3 years ago
12

150 is 15% of what number

Mathematics
2 answers:
gayaneshka [121]3 years ago
4 0
Answer: 1000

Explanation: Create an Equation.
150=0.15x

Solve for X

150/0.15 = 0.15x/0.15

x=1000
Darya [45]3 years ago
3 0

Answer:

1,000

Step-by-step explanation:

15%

Convert to a decimal

0.15

Mark the unknown as P and write an equation

0.15P = 150

Divide by 0.15

P = 1,000

The number is 1000

Hope this was useful to you!

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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
How do I do this?need help​
Lelu [443]
I have no clue at all
8 0
3 years ago
Please help me out :c - I will mark brainliest
andrew-mc [135]

Answer:

6.6%

Step-by-step explanation:

6 0
3 years ago
What are the solutions 2x^2 +7x=4
elena55 [62]
So your equation is 2x^{2} +7x = 4. You need to simplify this answer.
So first off, do 2x times 2x.
2 x 2 = 4.
Your equation is now 4x + 7x = 4.
You're already off to a great start, so now let's add 4x + 7x. It is 11x.
Your equation is almost done! It's 11x = 4 right now.
Divide both sides by 11, and your answer is...
0.36363636 and so on, or you can round to the nearest hundreth, in which it will be

0.36.

I hope I helped!
8 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!!! Which statement about “Sepoys” is CORRECT?
Charra [1.4K]

Answer:

Im like 99% sure its B i had the assignment and got a 94

Step-by-step explanation:

5 0
3 years ago
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