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motikmotik
3 years ago
13

A Scale model of a building is 12 inches tall. The actual building is 160 feet tall. What is the scale factor of the model write

your answer as a fraction and simplest form
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
7 0

Answer:

133/10

Step-by-step explanation:

divide 160 and 12 then simplify your answer

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Sonya took out a mortgage of $65,000 at 7% for 25 years. What is the cost of the mortgage?
Vika [28.1K]

The cost of the mortgage is $81250

<h3>What are interests?</h3>


Interests are percentages of a principal

Given the following parameters

Principal = $65000

Rate = 7% = 0.07
Time = 5 years

<h3>Calculate the interest</h3>

I = PRT/100
I = 65000*0.07*25
I = 16,250

<h3>Determine the cost of the mortgage</h3>

Cost of mortgage = Principal + Interest

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5 0
2 years ago
Read 2 more answers
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

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What conclusion can be made based on this multiplication problem?
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Answer: Your answer is D

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Please find the area of the shaded region.
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here is the solution to the question

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