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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics

2 answers:

vodka [1.7K]3 years ago

8 0

Answer: A) y = 96,

The maximum number of moose the forest can sustain at one time.

<u>Step-by-step explanation:</u>

The horizontal asymptote (H.A.) is the value of y that the graph cannot cross.

Since the degree of the numerator equals the degree of the denominator, divide their coefficients to find the H.A.

$y=\dfrac{60}{0.625}\\\\\\\large\boxed{y=96}$

Oliga [24]3 years ago

7 0

The answer is A: y=96 The maximum number of moose that the forest can sustain at one time.

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Answer:

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Replcaing equation (3) into equation (2) we got:

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And solving for X from equation (3) we got:

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Step-by-step explanation:

For this problem we can work with the concentration of water and orange juice.

Let X the amount for the orange juice with 25% content and Y the amount for the orange juice with 5% of content

Using the concentration of orange juice we have:

$0.25 X + 0.05 Y = 20*0.08$ (1)

And for the water we have:

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If we solve for X from equation (1) we got:

$X = \frac{1.6 - 0.05Y}{0.25}= 6.4 -0.2 Y$ (3)

Replcaing equation (3) into equation (2) we got:

$0.75(6.4 -0.2 Y) +0.95 Y = 18.4$

And solving for Y we got:

$4.8 -0.15 Y +0.95 Y = 18.4$

$0.8 Y = 13.6$

$Y = 17$

And solving for X from equation (3) we got:

$X= 6.4 -0.2*17 = 3$

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration

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