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2 years ago

Can someone please answer this m

Mathematics

1 answer:

sweet-ann [11.9K]2 years ago

7 0

Answer:

5^-4

1 / 5^4

Step-by-step explanation:

5^3 / 5^7

We know a^b / a^c = a^(b-c)

5^(3-7)

5^-4

If you are not allowed to have negative exponents

We know a^-b = 1/a^b

1 / 5^4

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For f(x) = x2 and g(x) = (x − 5)2, in which direction and by how many units should f(x) be shifted to obtain g(x)? (5 points) Up

IgorC [24]

Answer:

5 units to the right.

Step-by-step explanation:

The x in f(x) is replaced by x - 5 to give g(x).

The - 5 will shift f(x) 5 units to the right.

3 0

2 years ago

How expensive is Maui? A newspaper gave the following costs in dollars per day for a random sample of condominiums located throu

Leviafan [203]

Answer:

mean=134.3

median=65.5

mode=60

Step-by-step explanation:

Mean is computing by adding the all data values and then divided by number of values

mean=sum of all values/number of values

There are 20 data values.

mean=(88+50+66+60+360+55+500+71+41+350+60+50+250+45+45+125+235+65+60+110)/20

mean=2686/20

mean=134.3

For calculating median we arrange the data in ascending order

41 45 45 50 50 55 60 60 60 65 66 71 88 110 125 235 250 350 360 500

n/2=20/2=10 is an integer

So, the median is the average of n/2 and (n/2)+1 value

The median is average of 10th and 11th value

median=(65+66)/2

median=65.5

Mode is the most repeated value and we see that number of times the values are repeated are

45= 2 times

50= 2 times

60= 3 times

Thus, the most repeated value is 60 and it is the mode of data.

Mode=60

4 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

2 years ago

Explain what happens when you round 4.999 to the nearest tenth

Allushta [10]

Tenth place is the first place after the decimal which is 4.999
^
The answer is 4.9

4 0

2 years ago

Read 2 more answers

What is the value of x? Please help! Thanks!

leonid [27]

Answer:

x=75

Step-by-step explanation:

We can use proportions to solve this problem. Put the side of the small triangle over the side of the large triangle.

42 50

------ = ----------

42+63 50+x

42 50

------ = ----------

105 50+x

Using cross products

42(50+x) = 50*(105)

2100+42x = 5250

Subtract 2100 from each side

2100-2100+42x = 5250-2100

42x =3150

Divide by 42

42x/42 = 3150/42

x = 75

8 0

3 years ago