Graph
quadratic function is of the form
In our f(x) there is no x term and constant so we put 0
The value of a=1 , b=0 and c=0
To find vertex , use formula
Plug in the values
=0
Now plug in x=0 in f(x) equation
=0
So vertex is (0,0)
Now we pick some number for x below and above 0
Make a table
x y=x^2
-2 4
0 0
2 4
Now plot all the points (-2,4) (0,0) and (2,4)
The graph is attached below
Answer:
You need to add everything so i can solve
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer: x^2 - 8x + 16
Let y = x-4
(x-4)^2 = (x-4)*(x-4)
(x-4)^2 = y*(x-4) ... replace one copy of (x-4) with y
(x-4)^2 = x*y - 4*y .... distribute
(x-4)^2 = x*( y ) - 4( y )
(x-4)^2 = x(x - 4) - 4(x - 4) ... replace y with x-4
(x-4)^2 = x^2-4x-4x+16 .... distribute
(x-4)^2 = x^2 - 8x + 16
Answer:
Cosine
Step-by-step explanation:
There are 2 angles present and 1 length present, therefore you would use cosine.