F(x) = 4 [cos (x)]^2 - 3 = 0
4[cos(x)]^2 = 3
cos(x) = √3 / 2
That happens in the first and fourth quadrants, for the angles 30 degrees and 330 degrees.
Answer: x = 30 degrees and x = 330 degrees
Answer: which question
Step-by-step explanation:
SA=4pir^2
d/2=r
d=7.4
7.4/2=3.7
SA=4pi3.7^2
SA=4pi13.69
SA=54.76pi
pi=3.14 for this question
SA=171.9464
closest one is B
172 cm^2
B IS ANSWER
Answer:
Step-by-step explanation:
Let h bet the # of hours worked
If Cynthia earns $13 per hour then her equation would be:
C = $13h
If Amy makes $1.5 more per hour then her equation would be:
A = $14.5x
Now lets plug in some numbers:)
A = $14.5(43.5)
A = $630.75
<h3>
Answer: False</h3>
==============================================
Explanation:
I'm assuming you meant to type out
(y-2)^2 = y^2-6y+4
This equation is not true for all real numbers because the left hand side expands out like so
(y-2)^2
(y-2)(y-2)
x(y-2) .... let x = y-2
xy-2x
y(x)-2(x)
y(y-2)-2(y-2) ... replace x with y-2
y^2-2y-2y+4
y^2-4y+4
So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4
--------------------------
Another approach is to pick some y value such as y = 2 to find that
(y-2)^2 = y^2-6y+4
(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2
0^2 = 2^2 - 6(2) + 4
0 = 4 - 6(2) + 4
0 = 4 - 12 + 4
0 = -4
We get a false statement. This is one counterexample showing the given equation is not true for all values of y.
