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Vedmedyk [2.9K]
2 years ago
9

Solve these pair of simultaneous equations y=x^2-x-1 and y=2-3x

Mathematics
2 answers:
brilliants [131]2 years ago
7 0
Y = x^2 - x - 1
y = 2 - 3x

2 - 3x = x^2 - x - 1
x^2 - x - 1 - 2 + 3x = 0
x^2 + 2x - 3 = 0
(x + 3)(x - 1) = 0

x + 3 = 0            y = 2 - 3x
x = -3                 y = 2 - 3(-3)
                          y = 2 + 9  
                          y = 11

x - 1 = 0            y = 2 - 3x
x = 1                 y = 2 - 3(1)
                         y = 2 - 3
                         y = -1

so ur solutions are : (-3,11) or (1,-1)

Gnom [1K]2 years ago
3 0
Compare both sides, 
x² - x - 1 = 2 - 3x
x² + 2x - 3 = 0
x² -x + 3x - 3 = 0
x(x - 1) 3(x - 1) = 0
(x - 1)(x+3) = 0
x = 1 or - 3

In short, Your Answers would be 1 & -3

Hope this helps!
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3x + 10y = 12, 3x - 8y = 12
weeeeeb [17]
Working attached below:

Hope this helps! Any questions let me know :)

6 0
2 years ago
Solve for x <br>x/3 = 5/8​
dlinn [17]

Answer:

x = 15/8

Step-by-step explanation:

x/3 = 5/8

Using cross products

8x = 3*5

8x = 15

Divide each side by 8

8x/8 = 15/8

x = 15/8

3 0
3 years ago
Read 2 more answers
twice a number plus another number is 310. The difference between the two numbers is 55. What are the two numbers
Masteriza [31]
T us assume the two numbers to be "x" and "y".
Then
2x + y = 310
And
x - y = 55
Let us take the second equation and find the value of x in relation to y.
x - y = 55
x = y + 55
Now let us put the value of x in the first equation, we get
2x + y = 310
2(y + 55) + y = 310
2y + 110 + y = 310
3y = 310 - 110
3y = 200
y = 200/3
   = 66 2/3
Now putting the value of y in the second equation, we get
x - y = 55
x - (200/3) = 55
3x - 200 = 55 * 3
3x = 165 + 200
x = 365/3
   = 121 2/3
So the value of x is 121 2/3 and the value of y is 66 2/3

3 0
3 years ago
Read 2 more answers
Two planes are flying away from Toronto Pearson International Airport. The Air Canada
erica [24]

Answer:

1832 miles

Step-by-step explanation:

First we need to find the angle between the routes of the planes.

If one is N30°W and the other is S45°W, we can find the angle between the routes with the following equation:

30 + angle + 45 = 180

angle = 105°

Then, we need to find the distance travelled by each plane, using the formula:

distance = speed * time

The time is 1.5 hours, so we have that:

distance1 = 800 * 1.5 = 1200 km

distance2 = 750 * 1.5 = 1125 km

Now, to find the distance between the planes, we can use the law of cosines:

distance^2 = 1200^2 + 1125^2 - 2*1200*1125*cos(105)

distance^2 = 3356214.43

distance = 1832 miles

5 0
3 years ago
Determine how the next term in each sequence can be found 1.5, 3.9, 6.3, 8.7​
scoray [572]

Answer:

The next term in the sequence can be determined by subtracting 1.5 from 3.9 which is 2.4 and then you test it and say 3.9 plus 2.4 is 6.3 then plus 2.4 is 8.7 then the next term would be 11.11

5 0
2 years ago
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