Solve these pair of simultaneous equations y=x^2-x-1 and y=2-3x
2 answers:
Y = x^2 - x - 1
y = 2 - 3x
2 - 3x = x^2 - x - 1
x^2 - x - 1 - 2 + 3x = 0
x^2 + 2x - 3 = 0
(x + 3)(x - 1) = 0
x + 3 = 0 y = 2 - 3x
x = -3 y = 2 - 3(-3)
y = 2 + 9
y = 11
x - 1 = 0 y = 2 - 3x
x = 1 y = 2 - 3(1)
y = 2 - 3
y = -1
so ur solutions are : (-3,11) or (1,-1)
Compare both sides,
x² - x - 1 = 2 - 3x
x² + 2x - 3 = 0
x² -x + 3x - 3 = 0
x(x - 1) 3(x - 1) = 0
(x - 1)(x+3) = 0
x = 1 or - 3
In short, Your Answers would be 1 & -3
Hope this helps!
You might be interested in
Answer:
B) 2/3=x/4
Step-by-step explanation:
Since the figures are similar, we can use ratios to solve
2 x
----- = -----------
3 4
Answer:
11
Step-by-step explanation:
just do it
65 ÷ 1.5 = 43.333333...
Hope this helps you!
Always remember you are a Work Of Art!
-Nicole :) <3
Here is the answer to you question