Answer:
a=
Step-by-step explanation:
As we have 2 of the angles, we can find the third. The measure of the third angle is 45 degrees.
As this is the same measure as the other, that means that the side length will be the same.
Now was have two side lengths of 17 in a right triangle, so we can use the Pythagorean theorem to find a.
Recall that the pythagorean theorem states: 
In this case, a is 17, b is 17, and c is a
Knowing this, we can input our value into this formula and solve for a.

Answer:
wht grade
Step-by-step explanation:
Fractions
We are going to be checking each statement in order to find which of them are correct:
<h2>5/6 < 6/8 - 5/6 is smaller than 6/8</h2>
We can see that in the drawing 3/8 is smaller than 5/6. Then this statement is false.
<h2>
4/6 < 5/8 - 4/6 is smaller than 5/8</h2>
We can see that in the drawing 5/8 is smaller than 4/6. Then this statement is false.
<h2>
2/6 = 3/8 - 2/6 is equal to 3/8</h2>
We can see that in the drawing 3/8 is bigger than 2/6. Then this statement is false.
<h2>
3/6 = 4/8 - 3/6 is equal to 4/8</h2>
We can see that in the drawing 4/8 is equal to 3/6. Then this statement is true.
<h2>
Answer: 3/6 = 4/8</h2>
Answer:
12
Step-by-step explanation:
A 2 - sided counter ; (red, yellow)
A spinner (1,2,3,4,5,6)
Number of trials = 80
P(red and number > 3) :
P(red) = 1/2 ;
P(number >3) : numbers greater Than 3 = (4, 5, 6)
Hence, P(number <3) = 3 /6 = 1/2
Theoretical probability = 1/2 *1/2 = 1/4
Expected number of outcomes :
1/4 * number of trials
1/4 * 80 = 20
Experimental outcome :
Relative frequency = number of outcomes / number of trials
Relative frequency = 2/5
Hence,
2/5 = number of outcomes / 80
Cross multiply :
160 = number of outcomes * 5
Number of outcomes = 160 /5 = 32
Actual outcomes = 32
Difference between actual and expected :
32 - 20 = 12
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181