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loris [4]
3 years ago
7

F(x)=x²-6x+17 [find(x+h)-f(x)]/h

17" id="TexFormula1" title=" f(x) = {x}^{2} - 6x + 17" alt=" f(x) = {x}^{2} - 6x + 17" align="absmiddle" class="latex-formula">
[find (x+h) -f(x)]/h
Mathematics
1 answer:
jeyben [28]3 years ago
4 0
You should try an app called Photomath
You might be interested in
Which ordered pairs in the form (x, y) are solutions to the equation 3x−4y=21?
zmey [24]
We must plugin values:
3(7)-4(0)=21, is CORRECT since 7•3 is 21 and -4•0 is 0
3(11)-4(3)=21 is CORRECT since 3•11=33 and -4•3=-12 so 33-12=21
3(-3)-4(3)=21 is INCORRECT since 3•-3 is -9 and -4•3 is -12, -9-12 is -21
3(-1)-4(-6)=21 is CORRECT since 3•-1 is -3 and -4•-6 is 24 and so 24-3=21
4 0
4 years ago
Read 2 more answers
In ΔUVW, u = 44 inches, ∠W=56° and ∠U=117°. Find the length of v, to the nearest inch.
Arisa [49]

Answer:

The length of v is 6 inches

Step-by-step explanation:

Here, we want to calculate the length of v to the nearest inch

The best way to go about this is to use the sine rule

But before we proceed, we need the measure of angle V

Mathematically, since we have a triangle

W + U + V = 180

This is the sum of angles in a triangle

56 + 117 + V = 180

V = 180-56-117

V = 7 degrees

so we proceed to use sine rule to get the length of v

Mathematically;

v/Sin V = u/Sin U

Thus;

v/sin 7 = 44/sin 117

v = 44sin 7/sin 117

v = 6.018

This is approximately 6 inches

4 0
3 years ago
Read 2 more answers
The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth
Bess [88]

Answer:

Perimeter of given regular hexagon is <em>48.5 ft</em>.

Step-by-step explanation:

Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.

<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

In other words,

\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE are equilateral \triangle s.

Area of an equilateral \triangle is defined as :

\dfrac{\sqrt{3}}{4} \times a^{2}

Where <em>a </em>is the side of \triangle.

Area of hexagon = 6 \times \dfrac{\sqrt{3}}{4}\times a^{2}

We are given that area of hexagon = 169.74 ft^{2}

Let <em>s </em>be the side of hexagon.

\Rightarrow 6 \times \dfrac{\sqrt{3}}{4}s^{2} = 169.74 ft^{2}\\\Rightarrow s = 8.08 ft

A regular Hexagon is made up of 6 equal sides, so

Perimeter of a regular hexagon = 6 \times side

Perimeter = 6 \times 8.08

\Rightarrow 48.5 ft

So, perimeter of given regular hexagon is 48.5 ft.

6 0
3 years ago
PLEASE HELP 25 POINTS
Tju [1.3M]
Top angle = 180-112 = 68
Bottom angle = 180 - 126 = 54

Sum of angles in a triangle = 180 sooo
68+54+m=180
122+m=180
m=180-122
m=58

Therefore, angle m = 58
3 0
3 years ago
HELP PLEASEEE <br> ITS IXL AND I DONT GET IT
Rudik [331]

Answer:

mass is less than the red

speed is equal

energy is less than

Step-by-step explanation:

Hope this helps!

3 0
3 years ago
Read 2 more answers
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