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2 years ago

When a lilac bush is planted, it is 24 inches tall. Each month, it grows 6 inches taller. How tall will It get over time?

Mathematics

2 answers:

Bingel [31]2 years ago

3 0

Answer:

Dependent variable: time(months) or $t$

Independent variable: 6

Step-by-step explanation:

$h=24+6t$

(h=height)

nekit [7.7K]2 years ago

3 0

Dependent variable: height
Independent variable: time
Equation: height = 6 x time + 24

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in an examination 60% exam in failed in maths 55% failed in English and 25 failed in both subjects if none of the exam in past i

masha68 [24]

Answer:

60% x 25

55 % x 25

10 in english

25 is total and rest will be math

so 25-10 = 15

15 students failed math

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3 years ago

What is the image of (-8, 2) after a reflection over the y-axis?

BARSIC [14]

Answer:

(8, 2)

Step-by-step explanation:

When taking a point and reflecting it over the y-axis, the x coordinate turns into its opposite.

(-8, 2) ⇒ (8, 2)

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3 years ago

Select the answer choice below that represents 5.9 x 10-4 in standard notation.

PIT_PIT [208]

This means that you have to move the decimal point 4 decimal places to the left, as denoted by the negative sign. Thus, this would add 3 zeros before 5. The answer would be 0.00059.

I hope the explanation was clear to you. Have a good day.

6 0

3 years ago

A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula

Ilia_Sergeevich [38]

Answer: A. $A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}$

B. A'(5) = 1.76 cm/s

Step-by-step explanation: Rate of change measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

$A=\pi.r^{2}$

So to find the rate of the area:

$\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}$

$\frac{dA}{dr} =2.\pi.r$

Using $r(t)=3-\frac{363}{(t+11)^{2}}$

$\frac{dr}{dt}=\frac{726}{(t+11)^{3}}$

Then

$\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]$

$\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}$

Multipying and simplifying:

$\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$

The rate at which the area is increasing is given by expression $A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$ .

B. At t = 5, rate is:

$A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}$

$A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}$

$A'(5)=\frac{2408693760\pi}{4294967296}$

$A'(5)=1.76268$

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0

3 years ago

Sumas y restas w+y=9 3w-y=11

Westkost [7]

Answer:

w = 5

y = 4

Step-by-step explanation:

w+y=9

3w-y=11

4w = 20

w = 5

y = 4

3 0

3 years ago