Sum of 2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so
x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4
the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=

for x²-4x+16=0
x=

x=

x=

x=

x=

x=

the roots are
x=-4 and 2+2i√3 and 2-2i√3
Answer:
The required graph is shown below.
Step-by-step explanation:
Consider the provided equation 
We need to draw the graph of the equation.
Put x=0 in the above equation.


The coordinate is (0,2).
Put y=0 in the given equation.



The coordinate is (
,0).
Now draw the graph by using the above coordinates.
The required graph is shown below.
Answer:
8, 40 , 50
Step-by-step explanation:
the measure of A is 90°
so 5x + 7x - 6 = 90
now.. to find the x
5x + 7x - 6 = 90
5x + 7x = 90 + 6
12x = 96
x = 96/12
x = 8
so the measure of angle A1 is (5*8) = 40
the measure of angle A2 is (7*8-6) = 50
finaly the angle A is (50+40) = 90
Answer:Mark brainliest please
Answer is - 0.5
Step-by-step explanation: