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Pie
3 years ago
11

A. Solve -8=(X + 2)/4

Mathematics
1 answer:
valkas [14]3 years ago
6 0

9514 1404 393

Answer:

  a) x = -34

  b) -8 = x/4 +2/4; x = -34

  c) solving without the rewrite is easier, it takes fewer steps and eliminates fractions right away

Step-by-step explanation:

a) -32 = x +2 . . . . multiply by 4

  -34 = x . . . . . . . subtract 2

__

b)

  -8 = \dfrac{x+2}{4}\qquad\text{given}\\\\\boxed{-8=\dfrac{x}{4}+\dfrac{2}{4}}\qquad\text{right side as sum of fractions}\\\\\dfrac{-17}{2}=\dfrac{x}{4}\qquad\text{subtract $\dfrac{1}{2}$}\\\\\boxed{-34=x}

__

c) Solving the equation of (a) directly takes 2 steps. Rewriting and then solving takes 3 steps, and involves fractions at every step. The equation of part (a) is easier to solve without the rewrite.

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Step-by-step explanation:

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A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in
Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

\frac{dr}{dt} =\frac{1}{2} --- rate of the radius

\frac{dh}{dt} =-\frac{1}{3} --- rate of the height

r = 2

h = \frac{1}{3}

Required

Determine the rate of change of the cone volume

The volume of a cone is:

V = \frac{\pi}{3}r^2h

Differentiate with respect to time (t)

\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})

Substitute values for the known variables

\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)

\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}

\frac{dV}{dt} = -\frac{88}{63}

\frac{dV}{dt} =-1.396in^3/min

The volume is decreasing at the rate of 1.396 cubic inches per minute

3 0
3 years ago
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