Step 1: We make the assumption that 498 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$x.
Step 3: From step 1, it follows that $100\%=498$100%=498.
Step 4: In the same vein, $x\%=4$x%=4.
Step 5: This gives us a pair of simple equations:
$100\%=498(1)$100%=498(1).
$x\%=4(2)$x%=4(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{498}{4}$
100%
x%=
498
4
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{4}{498}$
x%
100%=
4
498
$\Rightarrow x=0.8\%$⇒x=0.8%
Therefore, $4$4 is $0.8\%$0.8% of $498$498.
Answer: The correct option is D, i.e.,30.
Explanation:
It the given equation we have two units l and dl.
Where l represents the liter and dl represents the deciliter. These are the volume units.
We know that,
1 liter = 10 deciliter
It means,
1 l = 10 dl
Multiply both sides by 3,
1\times 3 l = 10\times 3 dl
3 l = 30 dl
Therefore, the correct option is D and 3 l = 30 dl.
Answer:
-7x/6
Step-by-step explanation:
x/2-5x/3
Taking LCM
3x/6-10x/6
(3x-10x)/6
-7x/6
Answer:
Part a) The measure of the missing angle is
Part b) The triangle of the figure is a right triangle
Part c) The triangle of the figure is a scalene triangle
Step-by-step explanation:
we know that
The sum of the interior angles of a triangle is equal to
so
Let
x------> the missing angle
we know that
solve for x
The triangle of the figure is a right triangle --------> by its angles
Because the triangle has an angle measure of
The triangle of the figure is a scalene triangle --------> by its sides
Because the three angles and the three sides measures are different
Answer:
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.
Step-by-step explanation:
Volume of the Cylinder=400 cm³
Volume of a Cylinder=πr²h
Therefore: πr²h=400
Total Surface Area of a Cylinder=2πr²+2πrh
Cost of the materials for the Top and Bottom=0.06 cents per square centimeter
Cost of the materials for the sides=0.03 cents per square centimeter
Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)
C=0.12πr²+0.06πrh
Recall:
Therefore:
The minimum cost occurs when the derivative of the Cost =0.
r=3.17 cm
Recall that:
h=12.67cm
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.