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Alex Ar [27]
3 years ago
5

Mon Tue Wed Thur Fri Sat Sun –2 –6 –3 2 6 –7 0 a. Arrange the temperatures in order from coldest to warmest. b. On a day in Janu

ary, the low temperature in Minneapolis, MN was 11 degrees below zero (in degrees Fahrenheit) and the low temperature in Albany, NY was 7 degrees below zero (in degrees Fahrenheit). When asked which city was colder, Jacob wrote: Albany was colder, because –7 < –11. Is Jacob correct? Explain your answer. c. The lowest temperature in New York City was recorded on February 9, 1934 at –15°F. The lowest temperature for Minneapolis was recorded on January 28, 1888 at –41°F. Which city was colder? Write an inequality to support your answer.
Mathematics
1 answer:
zvonat [6]3 years ago
7 0

Answer:

A.) -7, -6, -3, -2, 0, 2, 6

B.) Jacob is correct, the larger the negative number, the lower the number is. So, since -11 is smaller than -7, it will be colder.

C.) Minneapolis is colder since -41 is way lower than -15.

-41<-15

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You paint one third of a wall and one for seven hours at that rate how long will it take you to paint one wall
Anna [14]
We can put this word problem into an equation.

1/3x = 7

Now we just have to solve for x. To find x we need to multiply by three on both sides.

1/3x = 7
*3       *3
-------------
x = 21

So it will take 21 hours to paint one wall.



7 0
3 years ago
Read 2 more answers
If jummai is 12years old and Tunde is 8years old and they share 15bananas in the ratio of their ages how many will each have sho
bixtya [17]

Jummai and Tunde will each have 9 and 6 bananas respectively.

For the given ratio case we use the sharing ratio criterion to solve the problem.

Jummai is 12 years old.

Tunde is 8 years old.

Their ages are in ratio of;

                             A = 12 : 8

                             A =  3 : 2

The ratio's sum is 5.

15 bananas total are available for sharing.

Jummai will have x\\ bananas  x = (15 x 3/5) = 9

Tunde will have y bananas  y = (15 x 2/5) = 6

Jummai and Tunde will each have 9 and 6 bananas with them.

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brainly.com/question/13419413

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5 0
1 year ago
Find the value of this expression if x = 2 and<br> y= 1.
N76 [4]

Answer: 2/5

Step-by-step explanation:

xy^2

--------

5

If x = 2 and y = 1

x * y^2 2 × 1^2

----------- -----------

5 5

2

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5

6 0
3 years ago
. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
An equilateral triangle has three congruent sides. If sides are congruent, the opposite angles are congruent.
VladimirAG [237]

Answer:

B)law of detachment

Step-by-step explanation:

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