As x → -∞, y → -∞
as x → ∞, y → ∞
Answer:
there is no expression
Step-by-step explanation:
P(Vowel)=5/26
P(2 vowels with replacement)= (5/26)^2
= 25/676
=0.037
P(2 Vowels w/o replacement)=(5/26)(4/25)
=20/650
=0.031
The first event is independent
The second event is dependent
Answer:
17x+24 is your answer
Step-by-step explanation:
Answer:

Step-by-step explanation:
Expression to calculate the displacement 'd' is,
d = vt - 
By subtracting vt from both the sides of the equation.
d - vt = -
vt - d =
--------(1)
Multiplying with 2 on both the sides of the equation,
2(vt - d) = at² --------(2)
Dividing by 't²' on both the sides of the equation,

--------(3)
Therefore, expression to calculate the acceleration 'a' will be
