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Alex787 [66]
2 years ago
7

Estimate the size of a crowd at a political rally that occupies a rectangular space with dimensions of 200 feet by 300 feet (to

the nearest whole number).
Assume that 25 people occupy a square measuring 10 feet by 10 feet.
A) 5,000 people
B) 7,500 people
C) 15,000 people
D) 30,000 people
Mathematics
1 answer:
vovikov84 [41]2 years ago
6 0

Answer:

C -15,000

Step-by-step explanation:

25 people occupy 100 ft2

Dimensions of venue: 200 x 300 = 60,000

100 ft2

25 people

=

60,000 ft2

x people

x = 15,000 people

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Please answer this for me and show me the work.
Gala2k [10]
Ok. No problem. I will answer anything u got
4 0
3 years ago
Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar
oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 18 means that N = 18

9 are carrying nuclear weapons, which means that k = 9

9 are destroyed, which means that n = 9

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021

P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0
3 years ago
Complete the steps to solve for x.
hram777 [196]

Answer:

-0.49x+0.19x=6.6

-0.3x=6.6

x=-22

5 0
2 years ago
What is the slope of the line through the points (–2, –1) and (8, –3)?
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Find the slope, denoted m

This is done by using the formula m = (y2 - y1)/(x2 - x1)

The slope for this problem is

m = [-3 - (-1)]/[8 - (-2)]  

m = -2/10 = -1/5

7 0
3 years ago
1.2million users of social media via mobile devices were added each day. How many users added on an average each second
Pachacha [2.7K]

Answer: 14 new users are added per second

Step-by-step explanation:

1,200,000/24 = 50000

50000/60 = 833.333333333

833.333333333/60 = 13.8888888889

then round because it said on average

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so on average 14 new users are added per second.

5 0
3 years ago
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