(6,-5) is a point on the terminal side of 0. Find the exact values of cos0, csc0, and tan0.

Mathematics

2 answers:

JulijaS [17]2 years ago

8 0

Answer:

Solutions given:

(6,-5)=(x,y)

r= $\sqrt{6²+(-5)²}=\sqrt{61}$

Now

Sin θ= $\frac{y}{r}$ = $\frac{-5}{\sqrt{61}}$

Cosθ= $\frac{x}{r}$ = $\frac{6}{\sqrt{61}}$

CSC θ= $\frac{r}{y}$ = $\frac{\sqrt{61}}{-5}$

Tan θ=θ= $\frac{y}{x}$ = $\frac{-5}{6}$

Note:

p=y

b=x

h=r

Dmitrij [34]2 years ago

4 0

point (6, -5) => x = 6, y = -5

r =√6² +(-5)² = √(36+25)=√61

the exact value of :

cos 0 = x/r = 6/√61 = 6/61 √61

csc 0 = r/y = √61/(-5) = -1/5 √61

tan 0 = y/x = -5/6

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IrinaVladis [17]

Answer:

Step-by-step explanation:

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