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Natasha2012 [34]
2 years ago
15

(6,-5) is a point on the terminal side of 0. Find the exact values of cos0, csc0, and tan0.

Mathematics
2 answers:
JulijaS [17]2 years ago
8 0

Answer:

Solutions given:

(6,-5)=(x,y)

r=\sqrt{6²+(-5)²}=\sqrt{61}

Now

Sin θ=\frac{y}{r}=\frac{-5}{\sqrt{61}}

Cosθ=\frac{x}{r}=\frac{6}{\sqrt{61}}

CSC θ=\frac{r}{y}=\frac{\sqrt{61}}{-5}

Tan θ=θ=\frac{y}{x}=\frac{-5}{6}

Note:

p=y

b=x

h=r

Dmitrij [34]2 years ago
4 0

point (6, -5) => x = 6, y = -5

r =√6² +(-5)² = √(36+25)=√61

the exact value of :

cos 0 = x/r = 6/√61 = 6/61 √61

csc 0 = r/y = √61/(-5) = -1/5 √61

tan 0 = y/x = -5/6

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