Answer: In the exact order up to down: 80, 74, 110, 96, 80
Step-by-step explanation:
Do the equation
360=(x-6)+(x+30)+1.2x+x
we can simplify by doing
360=(x-6)+(x+30)+2.2x
=360=x-6+x+30+2.2x
=360=4.2x+24
=336=4.2x
=80=x
x=80
I just started brainly and I want to help more people with their questions please just give a thanks or a rating to keep me going and help more people.
The equation would be (x+4)+x=18. X stands for the amount of pears Wilma bought, and (x+4) is the amount of pears Tania bought (because she bought four more pounds than Wilma).
(X+4)+x=18
2x+4=18 (now you subtract four from both sides)
2x=14 (to get x by itself, divide both sides by 2)
X=7
Wilma bought 7 pounds of pears :3
Change X and Z. X is first evening
Y is second
Z is third evening
Answer:
$18.36
Step-by-step explanation:
In this question, we have to find the cost of the cake for the customer who orders a month early.
We know that the original price of the cake is $30.
We also know that there was a 28% discount and a 15% discount added to the purchase.
Remember, You don't add discount percentages together, you discount the prices separately.
Solve:
First, apply the 28% discount.
30 · 0.28 = 8.40
30 - 8.40 = 21.60
Now apply the 15% discount to the new price.
21.60 · 0.15 = 3.24
21.60 - 3.24 = $18.36
They needed to pay $18.36 for the cake.
I think you meant to say

(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:
