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horsena [70]
3 years ago
14

Let f(w) = 2w^3 - 5. What is f(4)?

Mathematics
2 answers:
Serga [27]3 years ago
4 0

Answer:

f(4) =123

Step-by-step explanation:

first your going to put in 4 for every w

then, think of PEMDAS.

after you solve your parenthesis, then exponents Multiply/devide Then, add/subtract.

2(4)^3 -5

2* 64 -5

128 - 5

123 = f(4)

ZanzabumX [31]3 years ago
3 0
F(4) = 2(4)^3 -5
= 2(64) -5

= 128-5
= 123

Hope this helps!
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guapka [62]

Answer:

<u>The system has two solutions:</u>

<u>x₁ = 5  ⇒ y₁ = -10</u>

<u>x₂ = -2 ⇒ y₂ = 11</u>

Step-by-step explanation:

Let's solve the system of equations, this way:

y = -3x + 5

y = x ² - 6x - 5

Replacing y in the 2nd equation:

y = x ² - 6x - 5

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(3 +/- √(9 -4 * 1 * -10))/2 * 1

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(3 +/- 7)/2

x₁ = 10/2 = 5

x₂ = -4/2 = -2

x₁ = 5  ⇒ y₁ = -10

x₂ = -2 ⇒ y₂ = 11

<u>As we can see the system has two different solutions</u>

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Answer:

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Step-by-step explanation:

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