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horsena [70]
4 years ago
14

Let f(w) = 2w^3 - 5. What is f(4)?

Mathematics
2 answers:
Serga [27]4 years ago
4 0

Answer:

f(4) =123

Step-by-step explanation:

first your going to put in 4 for every w

then, think of PEMDAS.

after you solve your parenthesis, then exponents Multiply/devide Then, add/subtract.

2(4)^3 -5

2* 64 -5

128 - 5

123 = f(4)

ZanzabumX [31]4 years ago
3 0
F(4) = 2(4)^3 -5
= 2(64) -5

= 128-5
= 123

Hope this helps!
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2 years ago
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<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

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3 years ago
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Answer:

Step-by-step explanation:

The first expression has value 12

The second expression has value -6

The third expression has value

4

And finally the forth expression has value 1.14

((13 + 7) = 20

(12+4) = 16

16/ (20 - 16)= 16 / 4

16/4 = 4

8 0
3 years ago
Read 2 more answers
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