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2 years ago

Solve the system of equations: x – 4y = –8 and –3x + 12y = 24.

Mathematics

2 answers:

NISA [10]2 years ago

8 0

Answer:

<h2>C. There are an infinite number of solutions.</h2>

Step-by-step explanation:

$\left\{\begin{array}{ccc}x-4y=-8\\-3x+12y=24&\text{divide both sides by 3}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}x-4y=-8\\-x+4y=8\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad0=0\qquad\bold{TRUE}$

ale4655 [162]2 years ago

4 0

It should be C
Because when u multiply ( -3)*(x-4y= -8)

It’ll equal to -3x+12y=24 which is the same equation to the other one.
When the equations r the same, it means everything on the line is the solution for this system of equation.

You might be interested in

a. Determine whether the Mean Value Theorem applies to the function f (x )equals ln 15 xf(x)=ln15x on the given interval [1 comm

ivolga24 [154]

Answer:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

$c = e-1 \\$ = 1.71828

Step-by-step explanation:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

You are looking for a point $c$ such that

$\frac{1}{c} = \frac{\ln(15e)-\ln(15*1)}{e-1} = \frac{\ln(15e/15)}{e-1} = \frac{\ln(e)}{e-1} = \frac{1}{e-1}$

You have to solve for $c$ and get that

$c = e-1 \\$ = 1.71828

5 0

3 years ago

8. Write the equation of the line that is parallel to the line 2x + 5y = 15 and passes through the

marissa [1.9K]

Answer:

$\sf y = \bold -\frac{2}{5} x -3$

Explanation:

part A identification for slope:

$\sf 2x + 5y = 15$

$\sf 5y = -2x + 15$

$\sf y = \frac{-2x + 15}{5}$

$\sf y = -\frac{2 }{5} x+3$

comparing with slope intercept form: y = mx + b

we can find that here the slope is $\bold -\frac{2}{5}$

part B, solving the equation:

if the line is parallel, then the slope will be same.

given coordinates: ( - 10, 1 )

using the equation:

y - y₁ = m( x - x₁ )

$\sf y - 1 = \bold -\frac{2}{5} (x --10)$

$\sf y = \bold -\frac{2}{5} x -4 + 1$

$\sf y = \bold -\frac{2}{5} x -3$

Extra information:

check the image below. this proves that the line is parallel and passes through point (-10, 1). the blue line is question line and red the answer line.