Takumi plants a tree in his backyard and studies how the number of branches grows over
2 answers:
Answer:
t (years)= (10log 20/log 1000) in base 10
Step-by-step explanation:
N = 5 × 10^0.3t
N = 100 branches
100 = 5 × 10^0.3t
100/5 = 10^0.3t
20 = 10^0.3t
Taking log of both sides
Log 20 base 10 = 0.3t
Log 20 base 10 = (3/10)t
Multiply both sides by 10
10log 20 base 10 = 3t
Recall, log 1000 base 10 = 3
10 Log 20 base 10 = (log 1000 base 10)×t
t = (10Log 20 base 10)/(log 1000 base 10)
t (years)= (10log 20/log 1000) in base 10
The number of years it will take for the tree to have 100branches is (10log 20/log 1000) in base 10
Answer:
t = log 20 base 1.003
Step-by-step explanation:
since the tree was planted can be modeled by the following equation.
N = 5(100.3)^t
To calculate the number of years the tree will have 100 branches, we will substitute N for 100 and log both sides
100 = 5(1.003)^t
100 / 5 = (1.003)^t
20 = (1.003)^t
Log both sides
Log20 = log (1.003)^t
Log20 = t log 1.003
t = log 20 / log 1.003
Since both the numerator and denominator are expressed in base 10. Therefore
t = log 20 base 1.003
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