Question

A normal distribution has a mean of 15 and a standard deviation of 4. What percent of values are from 15 to 23

Answer 1

Answer:

47.72%

Step-by-step explanation:

Given

Mean (u) = 15

SD = 4

P(15<x<23) = $P(\frac{x-u}{\sigma}$

= $P(\frac{15-15}{4}$

=P(0<z< 2)

=P(z<2) - P(z<0)

Use standard normal table to find probability of the z score

= 0.9772 - 0.5

= 0.4772 $\approx$ 47.72%