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Vilka [71]
4 years ago
15

The correct Answer 1048576

Mathematics
2 answers:
lidiya [134]4 years ago
8 0
Answer 1048576 brooooo
Slav-nsk [51]4 years ago
6 0

Answer:

1048576 is correct!

Step-by-step explanation:

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Identify the lateral area and surface area of a regular triangular pyramid with base edge length 6 cm and slant height 13 cm.
Law Incorporation [45]

The lateral area is 117 square centimeters and the surface area is 292.72 square centimeters

<h3>How to determine the lateral area?</h3>

The given parameters are:

  • Base length (b) = 6
  • Slant height (l) = 13

The lateral area is calculated using:

Lateral = 0.5 * (Perimeter of base) * Slant height

This gives

Lateral = 0.5 * (3 * 6) * 13

Evaluate

Lateral = 117

Hence, the lateral area is 117 square centimeters

<h3>How to determine the surface area?</h3>

The surface area is calculated using:

Surface = l²√3

This gives

Surface = 13² * √3

Evaluate

Surface = 292.72

Hence, the surface area is 292.72 square centimeters

Read more about areas at:

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6 0
2 years ago
A 2.8 m ladder is to be laid against a wall so that the top of the ladder is 2 m up the wall. How far out from the base of the w
natta225 [31]

Given :

A 2.8 m ladder is to be laid against a wall so that the top of the ladder is 2 m up the wall.

To Find :

How far out from the base of the wall should the ladder be placed.

Solution :

We know, the angle between floor and height is 90° .

Now, length of ladder, l = 2.8 m .

Height of wall, h = 2 m .

Let, distance between base of the wall and ladder is b .

l^2 = h^2 + b^2\\\\b = \sqrt{l^2 - h^2}\\\\b = \sqrt{2.8^2 - 2^2}\ m\\\\b = 1.96 \ m

Hence, this is the required solution.

3 0
3 years ago
Can someone plz help me with 11,12,13 plz show work
dimaraw [331]

Answer:

  11.  x = -3+√37 ≈ 3.08276

  12.  x = 11.2

  13.  x = -6 +6√5 ≈ 7.41641

Step-by-step explanation:

In each case, the relation of interest is ...

  (distance to circle near) × (distance to circle far) = (distance to circle near) × (distance to circle far)

When there is only one point of intersection of the secant with the circle—because it is a tangent—then the product is the square of the length of the tangent.

11. 2(2+12) = x(x +6)

  x² +6x -28 = 0

  (x +3)² -37 = 0

  x = -3+√37 ≈ 3.08276

12. 5(5+x) = 9(9)

  5x +25 = 81

  x = 56/5 = 11.2

13. x(x +12) = 12(12)

  x² +12x -144 = 0

  (x +6)² -180 = 0

  x = -6 +√180 ≈ 7.41641

_____

<em>Comment on this secant rule</em>

This rule turns out to apply whether the point of intersection of the secant lines is outside the circle (as in these problems) or inside the circle (as in problem 9). The product of the two distances from the point of intersection to the circle is a constant for a given pair of intersecting secants/chords.

6 0
4 years ago
What is the quotient
katovenus [111]

Answer:

-3

Step-by-step explanation:

if u need an explanation, reply and i'll give it to you. If not, have a good day :)

5 0
3 years ago
Please help with this math question.​
V125BC [204]

The coordinate grid of the ordered pair is gotten from the combination of the y and X axis of the graph.

<h3>Finding of the ordered pair</h3>

Using the coordinates, an ordered pair for the given point is:

  • G = (4,3) because the 4 corresponds to the point in y axis and 3 on the X axis.

  • H= (10,8) because the 10 corresponds to the point in y axis and 8 on the X axis.

  • J= (6,4) because the 6 corresponds to the point in y axis and 4 on the X axis.

  • K= ( 2,1) because the 2 corresponds to the point in y axis and 1 on the X axis.

Learn more about coordinate grid here:

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7 0
2 years ago
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