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Andrei [34K]
3 years ago
13

a boat can travel 176 kilometers on 88 liters of gasoline. How much gasoline will it need to go 250 kilometers

Mathematics
1 answer:
bagirrra123 [75]3 years ago
8 0
It would need 125 litters of gasoline
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Inequalities part 2<br> I need help pls i dont understand
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Step-by-step explanation:

For y/x to be as high as possible, y must have the highest possible value and x must have the lowest possible value. (12 and 6)

Hence, y/x < 12/6, which is 2.

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Hence, y/x > 10/7.

Combining the 2 inequalities, we have 10/7 < y/x < 2.

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Answer:

Step-by-step explanation:

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What is 5x + 3x equal to
Gekata [30.6K]
The answer is 8x.
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A textbook store sold a combined total of 260 chemistry and physics textbooks in a week. The number of chemistry books sold was
Lynna [10]

Let:

x = Chemistry textbooks sold

y = Physics textbooks sold

The textbook store sold a combined total of 260, so:

x+y=260

The number of chemistry books sold was three times the number of physics textbooks sold, so:

x=3y

Let:

\begin{gathered} x+y=260_{\text{ }}(1) \\ x=3y_{\text{ }}(2) \end{gathered}

Replace (2) into (1):

\begin{gathered} 3y+y=260 \\ 4y=260 \\ y=\frac{260}{4} \\ y=65 \end{gathered}

Replace the value of y into (2):

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5 0
1 year ago
A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i
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Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

W=\frac{1}{2}kx^2

where k= spring constant

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Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k

4 0
3 years ago
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