Answer:
<em>if..then statement is used to make a decision when there is only two options. </em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>&</em>
<em>you have to write a program that have to choose from three options then we use if..then..else statement.</em>
<h3>I HOPE THIS WILL HELP YOU IF NOT THEN SORRY</h3>
HAVE A GREAT DAY :)
Answer:
There are two definitions from
Explanation:
1.) (of signals or data) expressed as series of the digits 0 and 1, typically represented by values of a physical quantity such as voltage or magnetic polarization.
2.) (of a clock or watch) showing the time by means of displayed digits rather than hands or a pointer.
I'm not sure if you meant "Digit". But if you did it would mean numbers or the places where numbers would go.
Hope this helps! (If not so sorry)
Answer:
if(isBalloon== true && isRed==false) //compare the value of isBalloon variable with true value and isRed variable value with false value.
System.out.println("Balloon");//Print Balloon
else if(isBalloon== true && isRed==true) //compare the value of isBalloon variable with true value and isRed variable value with also true value.
System.out.println("Red balloon");//Print Red Balloon
else // when no if condition match it will execute.
System.out.println("Not a balloon"); //Print Not a Balloon
Output:
Not a balloon
Explanation:
The "if-else" statement is defined above for the problem which is given on the question. The detailed explanation of the answer is described below--
- Firstly we need to check the "true" value for the "isBalloon" variable and "false" value for "isRed" variable. This is done in "if" statement separated with and(&&) operator which gives "true" when both are the true statement.
- Then we need to check the "true" value for the "isBalloon" variable and "isRed" variable. For this, we need to use "else if" statement which executes when "if" statement is false.
- Then we need to print the "Not a balloon" statement if both cases are false, for this, we use "else" statement which executes when the "if" and "else if" statement are false.
Answer:
The correct answer is letter "A": commit with fallback.
Explanation:
American Professor Alfred A. Marcus (born 1950) in his book "<em>The Future of Technology Management and the Business</em>" (2015) describes that hedging may be a strategy to shield businesses from the rapidly evolving world they face as a result of the continuous implementation of technology in the market. According to Marcus, there are 5 hedge approaches that firms should implement:
- Gamble on the most probable:<em> work on the product with the highest success rate.
</em>
- Take the robust route: <em>invest in as many products as possible.
</em>
- Delay until further clarity emerges:<em> waiting for a proper moment to react in front of market changes.
</em>
- <u>Commit with a fallback</u>:<em> adapt according to the market.
</em>
- Try to shape the future:<em> innovate.</em>